(3x−4)2+x(38x+2)(38x−2)=?
Let's solve this problem by simplifying each component separately:
First, simplify (3x−4)2 using the square of a difference formula:
(3x−4)2=(3x)2−2×3x×4+42
This becomes:
=9x2−38x+16
Next, simplify x(38x+2)(38x−2) using the difference of squares formula:
(38x+2)(38x−2)=(38x)2−22
Simplify further:
=98x−4
Including the factor of x, we have:
x(98x−4)=98x2−4x
Combine the results from both parts:
(9x2−38x+16)+(98x2−4x)
Simplify by combining like terms:
=9x2+98x2−38x−4x+16=x2−(38x+4x)+16=x2−(38x+12x)+16=x2−320x+16
Therefore, after simplifying, the expression becomes x2−320x+16.
The final solution is: x2−320x+16.
x2−632x+16