Factor the Expression: Simplifying 27mn^3+33m^2n^5

Polynomial Factoring with Variable Exponents

factor the following expression:

27mn3+33m2n5 27mn^3+33m^2n^5

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find the common factor
00:04 Factor 27 into factors 9 and 3
00:12 Factor 33 into factors 3 and 11
00:17 Break down power of 5 into power of 3 times power of 2
00:21 Mark the common factors
00:33 Take out the common factors from the parentheses
00:52 Take out the common factors from the parentheses

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

factor the following expression:

27mn3+33m2n5 27mn^3+33m^2n^5

2

Step-by-step solution

To solve the problem of factoring the expression 27mn3+33m2n5 27mn^3 + 33m^2n^5 , we'll follow these steps:

  • Step 1: Find the greatest common factor (GCF) of the coefficients.
  • Step 2: Determine the GCF of the variable terms.
  • Step 3: Factor out the GCF from the original expression.

Now, let's work through each step:

Step 1: Look at the coefficients 27 and 33. The greatest common factor of 27 and 33 is 3. This is the largest number that divides both 27 and 33 without leaving a remainder.

Step 2: Consider the variables in each term:

  • In 27mn3 27mn^3 , the variable part is mn3 mn^3 .
  • In 33m2n5 33m^2n^5 , the variable part is m2n5 m^2n^5 .

For the variable m m , the lowest power common to both terms is m1 m^1 .

For the variable n n , the lowest power common is n3 n^3 .

Therefore, the greatest common factor (GCF) of the variable part is mn3 mn^3 .

Step 3: Combine the GCF of the coefficients and the variable terms:

The GCF of the entire expression is 3mn3 3mn^3 .

Now, divide each term of the expression by this GCF:

  • Divide 27mn3 27mn^3 by 3mn3 3mn^3 , which leaves 9 9 .
  • Divide 33m2n5 33m^2n^5 by 3mn3 3mn^3 , which gives 11mn2 11mn^2 .

Thus, the factored form of the expression is:

3mn3(9+11mn2) 3mn^3 (9 + 11mn^2)

In conclusion, the solution to the problem is 3mn3(9+11mn2) 3mn^3 (9 + 11mn^2) .

3

Final Answer

3mn3(9+11mn2) 3mn^3(9+11mn^2)

Key Points to Remember

Essential concepts to master this topic
  • GCF Rule: Find greatest common factor of coefficients and variables separately
  • Variable Technique: Use lowest powers: m1 m^1 and n3 n^3 from terms
  • Check Division: Verify 27mn3÷3mn3=9 27mn^3 ÷ 3mn^3 = 9 and 33m2n5÷3mn3=11mn2 33m^2n^5 ÷ 3mn^3 = 11mn^2

Common Mistakes

Avoid these frequent errors
  • Using highest powers instead of lowest for variables
    Don't use m2n5 m^2n^5 as the variable GCF = impossible factoring! This creates terms that don't divide evenly into the original expression. Always use the lowest power of each variable that appears in all terms.

Practice Quiz

Test your knowledge with interactive questions

Break down the expression into basic terms:

\( 4x^2 + 6x \)

FAQ

Everything you need to know about this question

How do I find the GCF of coefficients like 27 and 33?

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List the factors: 27 = 3×9 and 33 = 3×11. The largest number that divides both is 3. You can also use prime factorization: 27 = 3³ and 33 = 3×11, so GCF = 3.

Why do I use the lowest power of each variable?

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The GCF must divide evenly into every term! If you use m2 m^2 , it won't divide into 27mn3 27mn^3 because that term only has m1 m^1 .

How can I check if my factoring is correct?

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Multiply your answer back out! If you get 3mn3(9+11mn2) 3mn^3(9 + 11mn^2) , distribute: 3mn3×9+3mn3×11mn2=27mn3+33m2n5 3mn^3 × 9 + 3mn^3 × 11mn^2 = 27mn^3 + 33m^2n^5

What if the terms don't seem to have a common factor?

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Look more carefully! Even if coefficients seem unrelated (like 27 and 33), they might share a factor. Also check for single variables like just 'm' or constants that divide both terms.

Can I factor out more than what I found?

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Only if the remaining expression in parentheses has another common factor. In this case, (9+11mn2) (9 + 11mn^2) cannot be factored further since 9 and 11 are coprime.

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