Factor the Expression: Simplifying 27mn^3+33m^2n^5

Question

factor the following expression:

27mn3+33m2n5 27mn^3+33m^2n^5

Video Solution

Step-by-Step Solution

To solve the problem of factoring the expression 27mn3+33m2n5 27mn^3 + 33m^2n^5 , we'll follow these steps:

  • Step 1: Find the greatest common factor (GCF) of the coefficients.
  • Step 2: Determine the GCF of the variable terms.
  • Step 3: Factor out the GCF from the original expression.

Now, let's work through each step:

Step 1: Look at the coefficients 27 and 33. The greatest common factor of 27 and 33 is 3. This is the largest number that divides both 27 and 33 without leaving a remainder.

Step 2: Consider the variables in each term:

  • In 27mn3 27mn^3 , the variable part is mn3 mn^3 .
  • In 33m2n5 33m^2n^5 , the variable part is m2n5 m^2n^5 .

For the variable m m , the lowest power common to both terms is m1 m^1 .

For the variable n n , the lowest power common is n3 n^3 .

Therefore, the greatest common factor (GCF) of the variable part is mn3 mn^3 .

Step 3: Combine the GCF of the coefficients and the variable terms:

The GCF of the entire expression is 3mn3 3mn^3 .

Now, divide each term of the expression by this GCF:

  • Divide 27mn3 27mn^3 by 3mn3 3mn^3 , which leaves 9 9 .
  • Divide 33m2n5 33m^2n^5 by 3mn3 3mn^3 , which gives 11mn2 11mn^2 .

Thus, the factored form of the expression is:

3mn3(9+11mn2) 3mn^3 (9 + 11mn^2)

In conclusion, the solution to the problem is 3mn3(9+11mn2) 3mn^3 (9 + 11mn^2) .

Answer

3mn3(9+11mn2) 3mn^3(9+11mn^2)