Fill the Blanks: Solve the Quadratic Equation (_+3)·(_-3) = x²-9

Fill in the missing element to obtain a true expression:

(+3)(3)=x29 (_—+3)\cdot(_—-3)=x^2-9

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Complete the missing value
00:03 We'll use the shortened multiplication formulas
00:07 Let's substitute X as A
00:11 and 9 as B
00:16 We'll extract the root and find A
00:22 A is the missing element
00:26 And this is the solution to the question

Step-by-step written solution

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1

Understand the problem

Fill in the missing element to obtain a true expression:

(+3)(3)=x29 (_—+3)\cdot(_—-3)=x^2-9

2

Step-by-step solution

To solve this problem, let's use the difference of squares formula, which is (a+b)(ab)=a2b2 (a + b)(a - b) = a^2 - b^2 . Given the equation (+3)(3)=x29(_ + 3)(_- 3) = x^2 - 9, we can compare it to the formula:

  • a2=x2 a^2 = x^2 implies a=x a = x .
  • b2=9 b^2 = 9 implies b=3 b = 3 .

This means the expression (+3)(3)(_ + 3)(_- 3) should represent (x+3)(x3)(x + 3)(x - 3), satisfying the equation through the difference of squares formula.

Thus, the missing element to obtain a correct expression is x x .

3

Final Answer

x x

Practice Quiz

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Solve:

\( (2+x)(2-x)=0 \)

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