Find Missing Numbers: Before and After 81000 in Sequence

Number Sequences with Large Integer Values

Complete the previous and following number:

,81000, \Box,81000,\Box

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Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Complete the previous and following number:

,81000, \Box,81000,\Box

2

Step-by-step solution

To solve this problem, we'll follow these steps:

  • Step 1: Calculate the predecessor of 81,000.
  • Step 2: Calculate the successor of 81,000.

Now, let's work through each step:
Step 1: The predecessor of 81,000 is obtained by subtracting 1 from it:
81,0001=80,999 81,000 - 1 = 80,999 .
Therefore, the predecessor is 80,999 80,999 .

Step 2: The successor of 81,000 is obtained by adding 1 to it:
81,000+1=81,001 81,000 + 1 = 81,001 .
Therefore, the successor is 81,001 81,001 .

Therefore, the solution to the problem is that the numbers are 80,999 80,999 and 81,001 81,001 .

The correct choice from the options provided that matches this result is:

Choice 3: 80,999,81,001 80,999, 81,001

3

Final Answer

80999,81001 80999,81001

Key Points to Remember

Essential concepts to master this topic
  • Rule: Predecessor is found by subtracting 1 from given number
  • Technique: For 81,000: predecessor is 81,000 - 1 = 80,999
  • Check: Verify sequence flows: 80,999 → 81,000 → 81,001 counts correctly ✓

Common Mistakes

Avoid these frequent errors
  • Subtracting or adding 10, 100, or 1000 instead of 1
    Don't subtract 10 from 81,000 to get 80,990 = skipping numbers in sequence! This creates gaps and gives wrong predecessor/successor. Always add or subtract exactly 1 for consecutive integers.

Practice Quiz

Test your knowledge with interactive questions

What number comes before 31,000?

FAQ

Everything you need to know about this question

What's the difference between predecessor and successor?

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The predecessor comes before a number (subtract 1), while the successor comes after (add 1). Think of them as the previous and next numbers in counting order.

Do I need to worry about commas in large numbers?

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Commas help with reading but don't affect the math. Whether you write 81,000 or 81000, the predecessor is still found by subtracting 1 to get 80,999 80,999 .

What if the number ends in zeros like 81,000?

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Handle it the same way! 81,0001=80,999 81,000 - 1 = 80,999 . The last zero becomes 9, and you borrow from the left digits just like in regular subtraction.

How can I check if my sequence is correct?

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Count by ones to verify: your first number + 1 should equal the middle number, and middle number + 1 should equal the last number. Each step increases by exactly 1.

Are there any tricks for finding predecessors quickly?

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Just subtract 1! For numbers ending in zero, remember that borrowing happens: the zero becomes 9, and you reduce the digit to its left by 1.

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