Find Number Groups with Average of 10: Selection Challenge

To solve the problem of determining which group of numbers has an average of 10, we will evaluate each provided choice:

• Choice 1: $10, 12, 11$
  Sum = $10 + 12 + 11 = 33$
  Number of elements = 3
  Average = $\frac{33}{3} = 11$
• Choice 2: $8, 10$
  Sum = $8 + 10 = 18$
  Number of elements = 2
  Average = $\frac{18}{2} = 9$
• Choice 3: $10, 0$
  Sum = $10 + 0 = 10$
  Number of elements = 2
  Average = $\frac{10}{2} = 5$
• Choice 4: $40, 0, 0, 0$
  Sum = $40 + 0 + 0 + 0 = 40$
  Number of elements = 4
  Average = $\frac{40}{4} = 10$

After evaluating all the choices, we find that Choice 4: $40, 0, 0, 0$ achieves an average of 10.

Therefore, the solution to the problem is $40, 0, 0, 0$.