Find Side AB in Right Triangle ABC with Hypotenuse 2 and Leg 1

To solve the problem, we will use the Pythagorean Theorem to calculate the length of side $AB$. According to the theorem, $AB^2 + AC^2 = BC^2$.

Given:

• Hypotenuse $BC = 2$
• One leg $AC = 1$

We need to find $AB$: $AB^2 + 1^2 = 2^2$

Solve for $AB^2$: $AB^2 + 1 = 4$

By subtracting 1 from both sides: $AB^2 = 4 - 1 = 3$

Taking the square root of both sides gives us: $AB = \sqrt{3}$

Therefore, the length of side $AB$ is $\sqrt{3}$.