Given the expression of the quadratic function
The symmetrical axis of the expression must be found.
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Given the expression of the quadratic function
The symmetrical axis of the expression must be found.
To solve this problem, we'll follow these steps:
Now, let's work through each step:
Step 1: The given quadratic function is , so and .
Step 2: We'll use the axis of symmetry formula .
Step 3: Plugging in our values, we get .
Therefore, the axis of symmetry for the quadratic is .
Given the expression of the quadratic function
The symmetrical axis of the expression must be found.
\( f(x)=-3x^2+3 \)
When there's no constant term, c = 0. This means the parabola passes through the origin (0,0). The axis of symmetry formula doesn't need the c value anyway!
Since -2.5 = -2½, think of it as negative two and one-half. The decimal 0.5 equals the fraction ½, so -2.5 becomes .
Check your signs carefully! With a = -5 and b = -25, you get . Double negatives matter!
Yes! Factor out -5x: . The zeros are x = 0 and x = -5, so the axis of symmetry is halfway between: .
The axis of symmetry shows you the x-coordinate of the vertex! It's the line where the parabola folds in half, and it helps you graph the function and find maximum or minimum values.
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