Determine the Axis of Symmetry of the Quadratic Function f(x) = x^2 + 4x + 1

Question

Given the expression of the quadratic function

The symmetrical axis of the expression must be found.

f(x)=x2+4x+1 f(x)=x^2+4x+1

Video Solution

Solution Steps

00:00 Find the axis of symmetry for the function
00:03 The axis of symmetry is the X value at the vertex point
00:06 The point where if you fold the parabola in half, both halves are identical
00:10 Let's examine the function coefficients
00:18 We'll use the formula to calculate the vertex point
00:23 We'll substitute appropriate values according to the given data and solve for X at the point
00:34 And this is the solution to the question

Step-by-Step Solution

To solve this problem, we'll apply the formula for finding the axis of symmetry for a quadratic function:

  • Step 1: Identify the coefficients.
    For the quadratic function f(x)=x2+4x+1 f(x) = x^2 + 4x + 1 , we have a=1 a = 1 and b=4 b = 4 .
  • Step 2: Use the formula for the axis of symmetry.
    The axis of symmetry for a quadratic function ax2+bx+c ax^2 + bx + c is given by x=b2a x = -\frac{b}{2a} .
  • Step 3: Substitute the values of a a and b b into the formula.
    Substitute b=4 b = 4 and a=1 a = 1 to get: x=42×1 x = -\frac{4}{2 \times 1} .
  • Step 4: Simplify to find the value of x x .
    This simplifies to x=42=2 x = -\frac{4}{2} = -2 .

Therefore, the axis of symmetry for the given quadratic function is x=2 x = -2 .

Answer

x=2 x=-2