Find the Coefficient of x² in y=-x²-3x+1: Quadratic Equation Analysis

a = coefficient of x²

b = coefficient of x

c = coefficient of the independent number


what is the value of a a in the equation

y=x23x+1 y=-x^2-3x+1

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Step-by-step video solution

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00:00 Find coefficient A
00:03 We'll use the quadratic equation formula
00:07 We'll compare the formula to our equation and find the coefficients
00:11 We can see that coefficient A is for the X² term
00:28 And this is the solution to the question

Step-by-step written solution

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1

Understand the problem

a = coefficient of x²

b = coefficient of x

c = coefficient of the independent number


what is the value of a a in the equation

y=x23x+1 y=-x^2-3x+1

2

Step-by-step solution

To determine the coefficient a a in the given quadratic equation y=x23x+1 y = -x^2 - 3x + 1 , follow these steps:

  • Step 1: Recognize the form of the quadratic equation as y=ax2+bx+c y = ax^2 + bx + c .
  • Step 2: Identify the x2 x^2 term in the equation y=x23x+1 y = -x^2 - 3x + 1 .
  • Step 3: Determine the coefficient of the x2 x^2 term, which is in front of x2 x^2 .

In the equation y=x23x+1 y = -x^2 - 3x + 1 , the term involving x2 x^2 is x2-x^2, where the coefficient a a is clearly 1-1.

Hence, the value of a a is a=1 a = -1 .

3

Final Answer

a=1 a=-1

Practice Quiz

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Solve the following equation:

\( 2x^2-10x-12=0 \)

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