In this article, we will learn the three most common ways to solve a quadratic function easily and quickly.
In this article, we will learn the three most common ways to solve a quadratic function easily and quickly.
The basic quadratic function equation is:
When:
- the coefficient of
- the coefficient of
- the constant term
a = coefficient of x²
b = coefficient of x
c = coefficient of the constant term
What is the value of \( c \) in the function \( y=-x^2+25x \)?
Find numbers that satisfy the following two conditions:
How do we proceed?
First of all, let's write down on the side:
*Relevant notation in the Word file*
Then–
Tip – It is recommended to use the trinomial method when
For more reading and practice on trinomials, click here!
And now let's practice!
Solve the quadratic function in front of you using trinomial:
Solution:
First of all, let's write down on the side:
*Relevant notation in the Word file*
Let's find all the numbers whose product is (and remember the negative numbers as well)
We get:
Now, let's check which pair of numbers from the pairs we found earlier will give us the sum (-9)
*Relevant notation in the Word file*
The pair of numbers that managed to meet both conditions is
We write the factorization:
The solutions:
Meet the quadratic formula:
All you need to do is arrange the parameters of the quadratic function, substitute into the equation once with a plus and once with a minus, and find the solutions.
To learn more about the quadratic formula, click here!
Let's practice!
In front of us is the quadratic function:
Let's solve it using the quadratic formula:
First, let's arrange the parameters:
Now, we substitute into the quadratic formula:
For the first time with plus-
The second time with minus:
We got solutions –
a = coefficient of x²
b = coefficient of x
c = coefficient of the independent number
what is the value of \( b \)in this quadratic equation:
\( y=4x^2-16 \)
a = coefficient of x²
b = coefficient of x
c = coefficient of the independent number
what is the value of \( c \) in this quadratic equation:
\( y=5+3x^2 \)
a = Coefficient of x²
b = Coefficient of x
c = Coefficient of the independent number
what is the value of \( b \) in the equation
\( y=3x^2+10-x \)
To use the method of completing the square, let's recall some of the formulas for the shortened multiplication:
Solution method with example:
Here is the function
In the example-
The appropriate formula for completing the square is:
Let's ask, what should we put as and to get ?
The answer is -
Let's expand this expression according to the formula for completing the square and get:
Now let's set the equation to 0 and solve:
and also
Solution 1:
Solution 2:
For more information on completing the square, click here!
a = Coefficient of x²
b = Coefficient of x
c = Coefficient of the independent number
what is the value of \( a \) in the equation
\( y=3x-10+5x^2 \)
a = coefficient of x²
b = coefficient of x
c = coefficient of the independent number
what is the value of \( c \) in this quadratic equation:
\( y=-5x^2+4x-3 \)
a = coefficient of x²
b = coefficient of x
c = coefficient of the independent number
what is the value of \( b \) in the equation
\( y=2x-3x^2+1 \)
Solve the following equation:
The parameters are expressed in the quadratic equation as follows:
aX2+bX+c=0
We substitute into the formula:
-5±√(5²-4*1*4)
2
-5±√(25-16)
2
-5±√9
2
-5±3
2
The symbol ± means that we have to solve this part twice, once with a plus and a second time with a minus,
This is how we later get two results.
-5-3 = -8
-8/2 = -4
-5+3 = -2
-2/2 = -1
And thus we find out that X = -1, -4
Solve the equation
The parameters are expressed in the quadratic equation as follows:
aX2+bX+c=0
We identify that we have:
a=1
b=0
c=9
We recall the root formula:
We replace according to the formula:
-0 ± √(0²-4*1*9)
2
We will focus on the part inside the square root (also called delta)
√(0-4*1*9)
√(0-36)
√-36
It is not possible to take the square root of a negative number.
And so the question has no solution.
No solution
Let's solve the given equation:
First, let's arrange the equation by moving terms:
Now, let's note that we can break down the expression on the left side using the short quadratic factoring formula:
This is done using the fact that:
So let's present the outer term on the right as a square:
Now let's examine again the short factoring formula we mentioned earlier:
And the expression on the left side of the equation we got in the last step:
Let's note that the terms indeed match the form of the first and third terms in the short multiplication formula (which are highlighted in red and blue),
But in order for us to break down the relevant expression (which is on the left side of the equation) using the short formula we mentioned, the match to the short formula must also apply to the remaining term, meaning the middle term in the expression (underlined):
In other words - we'll ask if it's possible to present the expression on the left side of the equation as:
And indeed it holds that:
So we can present the expression on the left side of the given equation as a difference of two squares:
From here we can take out square roots for the two sides of the equation (remember that there are two possibilities - positive and negative when taking out square roots), we'll solve it easily by isolating the variable on one side:
Let's summarize then the solution of the equation:
So the correct answer is answer a.
a = coefficient of x²
b = coefficient of x
c = coefficient of the constant term
What is the value of in the function ?
a = coefficient of x²
b = coefficient of x
c = coefficient of the independent number
what is the value of in this quadratic equation: