Find the LCM of Numerators: Calculating LCM(3, 5, 7)

LCM Calculation with Prime Numbers

Determine the least common multiple (LCM) of the following numerators:

3   7   5 \boxed{3} ~~~ \boxed{7} ~~~ \boxed{5}

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Step-by-step written solution

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1

Understand the problem

Determine the least common multiple (LCM) of the following numerators:

3   7   5 \boxed{3} ~~~ \boxed{7} ~~~ \boxed{5}

2

Step-by-step solution

To find the least common multiple (LCM) of the numbers 3, 7, and 5, we use the prime factorization method:

Prime factors of each number:

  • 3: 31 3^1
  • 7: 71 7^1
  • 5: 51 5^1

The LCM is the product of the highest powers of all prime factors:

31×71×51=3×7×5=105 3^1 \times 7^1 \times 5^1 = 3 \times 7 \times 5 = 105

3

Final Answer

105

Key Points to Remember

Essential concepts to master this topic
  • Prime Factorization: When all numbers are prime, LCM equals their product
  • Technique: 31×51×71=3×5×7=105 3^1 \times 5^1 \times 7^1 = 3 \times 5 \times 7 = 105
  • Check: 105 ÷ 3 = 35, 105 ÷ 5 = 21, 105 ÷ 7 = 15 ✓

Common Mistakes

Avoid these frequent errors
  • Adding prime numbers instead of multiplying
    Don't add 3 + 5 + 7 = 15! This gives a number that's not divisible by all three. When finding LCM of prime numbers, they share no common factors, so you must multiply them together: 3 × 5 × 7 = 105.

Practice Quiz

Test your knowledge with interactive questions

You have a pair of denominators, what is their least common multiple?

\( \boxed 2~~~\boxed5 \)

FAQ

Everything you need to know about this question

Why can't I just add the prime numbers together?

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Adding gives you a sum, not a multiple! The LCM must be divisible by each number. Since 15 ÷ 7 doesn't work, 15 isn't the LCM.

What makes this problem easier than other LCM questions?

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Since 3, 5, and 7 are all prime numbers, they share no common factors except 1. This means their LCM is simply their product: 3×5×7=105 3 \times 5 \times 7 = 105 .

How do I know 105 is really the smallest common multiple?

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Check that 105 is divisible by each number:

  • 105 ÷ 3 = 35 ✓
  • 105 ÷ 5 = 21 ✓
  • 105 ÷ 7 = 15 ✓
Any smaller number won't divide evenly by all three!

What if the numbers weren't all prime?

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Then you'd need to find the highest power of each prime factor. But here, each number appears only once as 31 3^1 , 51 5^1 , and 71 7^1 .

Is there a faster way than prime factorization?

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For prime numbers like these, just multiply them directly! Prime factorization shows why this works, but 3×5×7=105 3 \times 5 \times 7 = 105 is the quickest method.

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