Find the Linear Function Through (-3,-5) with 45-Degree Angle

Question

Which function represents a straight line that passes through the point (3,5) (-3,-5) and creates an angle of 45 degrees with the positive part of the x axis?

Video Solution

Solution Steps

00:00 Find the algebraic representation of the function
00:03 We'll use the formula to calculate slope according to the angle with X-axis
00:07 We'll substitute the angle according to the given data and calculate to find the slope
00:17 This is the line's slope
00:22 Now we'll use the line equation
00:26 We'll substitute the point according to the given data
00:31 We'll substitute the slope and solve to find the intersection point (B)
00:49 We'll isolate the intersection point (B)
00:53 This is the intersection point with Y-axis
00:58 Now we'll substitute the intersection point and slope in the line equation
01:09 And this is the solution to the question

Step-by-Step Solution

To solve this problem, let's start by finding the slope mm of the line. Since the line makes a 45-degree angle with the positive xx-axis, the slope m=tan(45)=1m = \tan(45^\circ) = 1.

Next, we will use the point-slope form of the line equation, which is given by:

yy1=m(xx1) y - y_1 = m(x - x_1)

where (x1,y1)=(3,5)(x_1, y_1) = (-3, -5) and m=1m = 1. Substituting these values, we have:

y+5=1(x+3) y + 5 = 1 \cdot (x + 3)

which simplifies to:

y+5=x+3 y + 5 = x + 3

Subtract 5 from both sides to put it into slope-intercept form y=mx+by = mx + b, we get:

y=x2 y = x - 2

Therefore, the function that represents the line through (3,5)(-3, -5) with a 45-degree angle with the xx-axis is y=x2 y = x - 2 .

Answer

y=x2 y=x-2