Find the Missing Coefficient: Solving ?(2x+y)=6x+3y

Fill in the missing value:

?(2x+y)=6x+3y ?(2x+y)=6x+3y

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Complete the missing values
00:03 Let's factor 6 into factors 2 and 3
00:14 Let's mark the common factors
00:24 Let's take out the common factors from the parentheses
00:28 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Fill in the missing value:

?(2x+y)=6x+3y ?(2x+y)=6x+3y

2

Step-by-step solution

To solve this problem, we need to equate the expression ?(2x+y) ?(2x+y) to 6x+3y 6x+3y and solve for the missing factor.

Step 1: Analyze the expression 6x+3y 6x + 3y .

  • Notice that both terms, 6x 6x and 3y 3y , have a common factor of 3.

Thus, we can factor the expression as 3(2x+y) 3(2x + y) .

Step 2: Equate the factored form 3(2x+y) 3(2x + y) with the original form ?(2x+y) ?(2x + y) .

  • If ?(2x+y)=3(2x+y) ?(2x + y) = 3(2x + y) , then the missing factor ? ? must be 3.

Therefore, the missing number that satisfies the equation ?(2x+y)=6x+3y ?(2x+y)=6x+3y is 3 3 .

3

Final Answer

3 3

Practice Quiz

Test your knowledge with interactive questions

Break down the expression into basic terms:

\( 4x^2 + 6x \)

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