Complete the number so that it is divisible by 3 without a remainder:
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Complete the number so that it is divisible by 3 without a remainder:
To solve this problem, we'll follow these steps:
Now, let's execute these steps:
Step 1: Calculate the sum of the known digits.
The given number format is . The known digits are 3, 5, and 2. Calculate their sum: .
Step 2: Determine the missing digit that completes the sum to be divisible by 3.
Let's denote the missing digit as . The total sum of the digits is . For the number to be divisible by 3, must also be divisible by 3.
Examine the possible values for :
The correct that results in a sum divisible by 3 is 2.
Step 3: Validate this result against the provided choices.
Among the choices given, is indeed an option. Thus, the correct missing digit is .
Therefore, the solution to the problem is that the missing digit is .
Determine if the following number is divisible by 3:
\( 352 \)
This works because of how our base-10 number system relates to multiples of 3. When you add digits, you're essentially finding the remainder when the number is divided by 3!
For single-digit problems like this, there's usually only one correct answer within the range 0-9. Calculate each possibility systematically to find which digit makes the sum divisible by 3.
Not necessarily! Since must be divisible by 3, you can use mental math: 12 is the next multiple of 3 after 10, so .
Look for sums that are multiples of 3: 3, 6, 9, 12, 15, 18, etc. You can also add the digits of the sum repeatedly until you get a single digit - if it's 3, 6, or 9, the original sum is divisible by 3!
Yes! The same principle applies - add all known digits, then determine what the missing digits must sum to in order to make the total divisible by 3. Just remember there might be multiple valid combinations.
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