Find the Missing Digits in 3?8?: Divisible by 9 Challenge

Divisibility Rules with Multiple Missing Digits

Complete the number so that it is divisible by 9 without a remainder:

3?8? 3?8?

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Complete the missing digits so that the number is divisible by 9
00:03 A number divisible by 9 is a number whose sum of digits is divisible by 9
00:06 Let's substitute the possibilities, sum them up, and check if it's divisible
01:28 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Complete the number so that it is divisible by 9 without a remainder:

3?8? 3?8?

2

Step-by-step solution

To determine the digits needed in the number 3?8?3?8? so that it is divisible by 9, follow these steps:

  • Step 1: According to the divisibility rule for 9, the sum of the digits in the number must be divisible by 9.
  • Step 2: Compute the sum of known digits: 3+8=113 + 8 = 11.
  • Step 3: Let the unknown digits be represented by xx and yy. The sum of all digits will be 11+x+y11 + x + y.
  • Step 4: For the number to be divisible by 9, 11+x+y11 + x + y must be a multiple of 9.
  • Step 5: Determine possible values for xx and yy so that the sum is as follows: 11 + x + y = 18 (next multiple of 9 after 11).
  • Step 6: Doing the arithmetic, we require x+y=7x + y = 7.
  • Step 7: Examine the possible digit combinations for xx and yy that sum to 7:
    - (x,y)=(0,7),(1,6),(2,5),(3,4),(4,3),(5,2),(6,1),(7,0)(x, y) = (0, 7), (1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1), (7, 0).
  • Step 8: Check given answer choices for these pairs and notice none match exactly.

Upon verifying these computations against the choices available, we conclude that the correct answer is None of the above.

3

Final Answer

None of the above

Key Points to Remember

Essential concepts to master this topic
  • Divisibility Rule: Sum of all digits must be divisible by 9
  • Technique: For 3?8? 3?8? , need 11+x+y=18 11 + x + y = 18 so x+y=7 x + y = 7
  • Check: Test all valid pairs (0,7), (1,6), (2,5), (3,4), (4,3), (5,2), (6,1), (7,0) ✓

Common Mistakes

Avoid these frequent errors
  • Only checking if individual digits work
    Don't just test if single digits make sense = missing valid combinations! This ignores that there are 8 different pairs that work. Always find the sum needed first, then identify all possible digit pairs that achieve it.

Practice Quiz

Test your knowledge with interactive questions

Will a number divisible by 6 necessarily be divisible by 3?

FAQ

Everything you need to know about this question

Why is the sum 18 and not some other multiple of 9?

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Since we have 3+8=11 3 + 8 = 11 , we need the next multiple of 9 that's greater than 11. That's 18! We could also use 27, but that would require x+y=16 x + y = 16 , which is impossible since the maximum is 9+9=18 9 + 9 = 18 .

How many correct answers are there for this problem?

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There are 8 different pairs that work: (0,7), (1,6), (2,5), (3,4), (4,3), (5,2), (6,1), and (7,0). This creates 8 different 4-digit numbers, all divisible by 9!

What if none of the given choices match my answer?

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That's exactly what happened here! When you solve correctly but none of the multiple choice options match your valid solutions, choose "None of the above" - it's a legitimate answer choice.

Can I use this method for any number divisible by 9?

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Yes! The divisibility rule for 9 always works: add up all digits, and if that sum is divisible by 9, then the entire number is divisible by 9. This works for any size number.

What if I need the digits to be different from each other?

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The problem doesn't specify that the digits must be different, so pairs like (0,7) and (7,0) are both valid. If uniqueness was required, it would be stated in the problem.

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