Complete the number so that it is divisible by 9 without a remainder:
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Complete the number so that it is divisible by 9 without a remainder:
To determine the digits needed in the number so that it is divisible by 9, follow these steps:
Upon verifying these computations against the choices available, we conclude that the correct answer is None of the above.
None of the above
Will a number divisible by 6 necessarily be divisible by 3?
Since we have , we need the next multiple of 9 that's greater than 11. That's 18! We could also use 27, but that would require , which is impossible since the maximum is .
There are 8 different pairs that work: (0,7), (1,6), (2,5), (3,4), (4,3), (5,2), (6,1), and (7,0). This creates 8 different 4-digit numbers, all divisible by 9!
That's exactly what happened here! When you solve correctly but none of the multiple choice options match your valid solutions, choose "None of the above" - it's a legitimate answer choice.
Yes! The divisibility rule for 9 always works: add up all digits, and if that sum is divisible by 9, then the entire number is divisible by 9. This works for any size number.
The problem doesn't specify that the digits must be different, so pairs like (0,7) and (7,0) are both valid. If uniqueness was required, it would be stated in the problem.
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