Select a compatible expression to show that a is greater than 3 but smaller than 7:
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Select a compatible expression to show that a is greater than 3 but smaller than 7:
First, we'll mark on the axis the expression
Then we'll mark on the axis the expression
We'll mark in orange the segment representing the requested expression:
All negative numbers appear on the number line to the left of the number 0.
It means 'a is greater than 3 AND less than 7'. The variable a must satisfy both conditions at the same time. So a could be 4, 5, 6, or any decimal between 3 and 7.
Because we use the < symbol, not ≤. The < symbol means 'strictly less than' or 'strictly greater than', so the endpoints are not included. If 3 and 7 were included, we'd write 3 ≤ a ≤ 7.
Look for the expression that shows both conditions: a > 3 AND a < 7. This is written as . Avoid single equalities like a = 7 or impossible ranges like 7 < a < 3.
Draw open circles at 3 and 7 (since they're not included), then shade the region between them. This shows all possible values of a that make both 3 < a and a < 7 true.
Yes! Try a = 5: Is 3 < 5? Yes. Is 5 < 7? Yes. Since both conditions are true, a = 5 is in our solution set. Values like 2.5 or 8 would fail one of the conditions.
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