Find Y-Axis Intersection: Solving y=(x-2)² Quadratic Function

Find the intersection of the function

$y=(x-2)^2$

With the Y

To determine the intersection of the function $y = (x-2)^2$ with the y-axis, we set $x = 0$, as the y-axis is defined by all points where $x = 0$.

Substituting $x = 0$ into the equation:

$y = (0 - 2)^2$

Simplifying this expression:

$y = (-2)^2 = 4$

Thus, the intersection point of the function with the y-axis is $(0, 4)$.

Therefore, the solution to the problem is $(0, 4)$.