Find Y-Axis Intersection: Solving y=(x-2)² Quadratic Function

Question

Find the intersection of the function

$y=(x-2)^2$

With the Y

00:08 Let's find where the function crosses the Y-axis.

00:12 Remember, at the Y-axis, X is always zero.

00:17 So, we'll substitute X equals zero into the equation to get the Y value.

00:26 This gives us the point where the function intersects the Y-axis.

00:33 And that's how we solve this problem!

To determine the intersection of the function $y = (x-2)^2$ with the y-axis, we set $x = 0$ , as the y-axis is defined by all points where $x = 0$ .

Substituting $x = 0$ into the equation:

$y = (0 - 2)^2$

Simplifying this expression:

$y = (-2)^2 = 4$

Thus, the intersection point of the function with the y-axis is $(0, 4)$ .

Therefore, the solution to the problem is $(0, 4)$ .

$(0,4)$