Find Y-Axis Intersection: Solving y=(x-2)² Quadratic Function

Question

Find the intersection of the function

$y=(x-2)^2$

With the Y

00:00 Find the intersection point of the function with the Y-axis

00:03 At the intersection point with the Y-axis, X = 0

00:06 Therefore, let's substitute X = 0 and solve to find the intersection point with the Y-axis

00:18 This is the Y value at the intersection point, we substitute X=0 as we set at the point

00:25 And this is the solution to the question

To determine the intersection of the function $y = (x-2)^2$ with the y-axis, we set $x = 0$ , as the y-axis is defined by all points where $x = 0$ .

Substituting $x = 0$ into the equation:

$y = (0 - 2)^2$

Simplifying this expression:

$y = (-2)^2 = 4$

Thus, the intersection point of the function with the y-axis is $(0, 4)$ .

Therefore, the solution to the problem is $(0, 4)$ .

$(0,4)$