The function
the most basic quadratic function:

the most basic quadratic function:
The family of parabolas
The basic quadratic function – with the addition of
In this family, we are given a quadratic function that clearly shows us how the function moves horizontally – how many steps it needs to move right or left.
represents the number of steps the function will move horizontally – right or left.
If is positive – (there is a minus in the equation) – the function will move steps to the right.
If is negative – (and as a result, there is a plus in the equation because minus times minus equals plus) – the function will move steps to the left.
In this quadratic function, we can see a combination of horizontal and vertical shifts:
: Determines the number of steps and the direction the function will move vertically – up or down.
positive – shift up, negative – shift down.
: Determines the number of steps and the direction the function will move horizontally – right or left.
What is the value of y for the function?
\( y=x^2 \)
of the point \( x=2 \)?
Meet the most basic quadratic function:
In this function:
The function is a smiling minimum function and its vertex is -
The axis of symmetry of this function is .
The increasing interval of the function – all the values where the function is increasing are:
The decreasing interval of the function – all the values where the function is decreasing are:
Positive interval: all except – you can see in the graph that the entire function is above the axis
Negative interval: none. The entire function is above the axis.
Let's continue to a similar function from the same family:
In this function:
The function is a sad maximum function and its vertex is
The axis of symmetry of this function is .
Increasing interval:
Decreasing interval:
Positive interval: None. The entire function is below the axis.
Negative interval: All except
Let's continue with another function from the same family:
In this function:
Its vertex is-
The axis of symmetry of this function is .
The larger is: the parabola will have a smaller opening – closer to its axis of symmetry.
The smaller is: the parabola will have a larger opening – farther from its axis of symmetry.
The function from this family has no horizontal or vertical shift because in every function from this family the vertex is
The family of parabolas
The basic quadratic function – with the addition of
In this function:
– represents the intersection point of the function with the axis.
The meaning of is a vertical shift up or down of the function from the vertex .
If is positive – the function will shift vertically up by the number of steps indicated by .
If is negative – the function will shift vertically down by the number of steps indicated by .
This function describes only vertical shifts up and down according to
Let's see an example:
In this function -
this means that the intersection point of the function with the axis is .
And actually – the function moves vertically steps up.
In this family, we are given a quadratic function that clearly shows us how the function moves horizontally – how many steps it needs to move right or left.
represents the number of steps the function will move horizontally – right or left.
If is positive – (there is a minus in the equation) – the function will move steps to the right.
If is negative – (and as a result, there is a plus in the equation because minus times minus equals plus) – the function will move steps to the left.
Let's see an example:
This function moves from the vertex , steps to the right
Let's see this in the figure:
In this quadratic function, we can see a combination of horizontal and vertical shifts:
: Determines the number of steps and the direction the function will move vertically – up or down.
positive – shift up, negative – shift down.
: Determines the number of steps and the direction the function will move horizontally – right or left.
Let's look at an example of combining two translations together:
For example, in the function:
The changes will be:
According to : the parabola will move steps to the left.
According to : the parabola will move steps up.
Let's see this in the illustration:
We can see that the vertex of the parabola is:
Complete:
The missing value of the function point:
\( f(x)=x^2 \)
\( f(?)=16 \)
Find the ascending area of the function
\( f(x)=2x^2 \)
Find the descending area of the function
\( f(x)=\frac{1}{2}x^2 \)
What is the value of y for the function?
of the point ?
To solve this problem, we'll follow these steps:
Now, let's work through each step:
Step 1: The given equation is . We need to substitute into this equation.
Step 2: Substitute to get . Calculate .
Therefore, the value of when is .
Hence, the solution to the problem is .
Complete:
The missing value of the function point:
To solve this problem, we'll follow these steps:
Now, let's work through each step:
Step 1: We start with the equation given by the function . We know , so we can write:
Step 2: To solve for , we take the square root of both sides of the equation:
Step 3: Solve for :
The square root of 16 is 4, so:
or
This gives us the two solutions: and .
Step 4: Compare these solutions to the answer choices. The correct choice is:
and
Therefore, the solution to the problem is and .
Find the ascending area of the function
To determine the intervals where the function is increasing, we will analyze the derivative of the function:
Step 1: Differentiate the function.
The derivative of is .
Step 2: Determine where .
To find the increasing intervals, set . Solving this inequality, we obtain .
Therefore, the function is increasing for .
Consequently, the correct answer is the interval where the function is increasing, which is .
0 < x
Find the descending area of the function
To solve the problem of finding the descending area of the function , we follow these steps:
Thus, the descending area (domain where the function is decreasing) for the function is .
The correct choice that matches this solution is: .
x < 0
Which chart represents the function ?
To solve the problem of identifying which chart represents the function , let's analyze the function and its graph:
After inspecting the charts:
Therefore, the chart that represents the function is Choice 4.
4