Finding Intervals of Increase for Parabola y = -2(x-4)² + 5 with Vertex (4,5)

The vertex of the parabola is at the point (4,5) \left(4,5\right) and the coefficient of x2 x^2 is 2 -2

Find the intervals of increase of the function

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1

Understand the problem

The vertex of the parabola is at the point (4,5) \left(4,5\right) and the coefficient of x2 x^2 is 2 -2

Find the intervals of increase of the function

2

Step-by-step solution

To solve this problem and find the intervals of increase for the function, let's follow these steps:

  • Step 1: Identify the nature of the parabola.
  • Step 2: Determine the intervals where the function is increasing.
  • Step 3: Provide a clear explanation of the result.

Now, let's dive into each step:
Step 1: We know the quadratic function opens downwards because the coefficient of x2 x^2 is 2-2, which is negative. This implies that the vertex is at a maximum point, and the parabola decreases on either side of the vertex.

Step 2: The vertex given is (4,5) (4, 5) . For parabolas that open downwards, the function is increasing to the left of the vertex. Therefore, the function is increasing for x<4 x < 4 .

Step 3: Therefore, the interval of increase for the parabola is x<4 x < 4 .

In conclusion, the interval where the function is increasing is x<4 x < 4 .

3

Final Answer

x<4 x<4

Practice Quiz

Test your knowledge with interactive questions

Note that the graph of the function shown below does not intersect the x-axis

The parabola's vertex is A

Identify the interval where the function is decreasing:

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