Here is a series of structures made of squares whose side length is 1 cm.
Is it possible to have a structure in the series that has 49 squares? If so, what element of the series is it?
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Here is a series of structures made of squares whose side length is 1 cm.
Is it possible to have a structure in the series that has 49 squares? If so, what element of the series is it?
To determine if it is possible to have a structure in the series with 49 squares, consider the sequence of numbers representing perfect squares: 1, 4, 9, 16, 25, 36, 49, etc. Here, each number represents the total number of 1 cm x 1 cm squares contained in an square.
The number 49 is indeed a perfect square, since . This means that a structure made up of 49 squares can indeed be represented as a square.
Therefore, it is possible to have a structure in the series that has 49 squares, and it corresponds to the 7th square in the sequence (since ), and this matches answer choice Yes, .
Yes,
Is there a term-to-term rule for the sequence below?
18 , 22 , 26 , 30
Check if the number is a perfect square! Take its square root - if you get a whole number, then it can form a square. For example: , so 49 squares make a 7×7 structure.
Element 7 means the 7th structure in the series, which is a 7×7 square containing unit squares. The element number always equals the side length!
No! Since is not a whole number, 50 is not a perfect square. Only perfect square numbers can form complete square structures.
Take the square root of the number of squares. If it's a whole number, that's your element position! For 49 squares: , so it's the 7th element.
Because we're building square structures! An n×n square always contains exactly unit squares. This creates the sequence: 1, 4, 9, 16, 25, 36, 49...
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