Linear Function y=(x+2)²: Graph Matching and Point Identification

Question

Match the function

y=(x+2)2 y=(x+2)^2

for the corresponding chart

222-2-2-2-4-4-4-2-2-21234

Video Solution

Solution Steps

00:00 Match the correct graph to the function
00:03 The term P equals (-2)
00:11 The term K equals (0)
00:16 X-axis intersection points according to the terms
00:19 We'll use the square of sum formulas to open the parentheses
00:25 The coefficient of X squared is positive, meaning a smiling parabola
00:33 Let's draw the function according to the intersection points and parabola type
00:40 And this is the solution to the question

Step-by-Step Solution

To solve this problem, we'll determine which graph represents the line given by y=(x+2)2 y=(x+2)^2 .

  • Step 1: The y-intercept for the function y=x+2 y = x + 2 is at point (0,2)(0, 2).

  • Step 2: Another point can be found by substituting x=4 x = -4 , giving y=4+2=2 y = -4 + 2 = -2 , so point (4,2)(-4, -2).

  • Step 3: Based on these points, we identify a slope of 2(2)0(4)=1 \frac{2 - (-2)}{0 - (-4)} = 1 .

  • Step 4: Check each graph to find the one that includes these details: y-intercept at 2 and another point at (4,2)(-4, -2).

Upon examining each option, we find that the graph matching these points and features corresponds to choice 3.

Thus, the correct graph is option 3.

Answer

3