Linear Function y=(x+2)²: Graph Matching and Point Identification

Match the function

y=(x+2)2 y=(x+2)^2

for the corresponding chart

222-2-2-2-4-4-4-2-2-21234

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Match the correct graph to the function
00:03 The term P equals (-2)
00:11 The term K equals (0)
00:16 X-axis intersection points according to the terms
00:19 We'll use the square of sum formulas to open the parentheses
00:25 The coefficient of X squared is positive, meaning a smiling parabola
00:33 Let's draw the function according to the intersection points and parabola type
00:40 And this is the solution to the question

Step-by-step written solution

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1

Understand the problem

Match the function

y=(x+2)2 y=(x+2)^2

for the corresponding chart

222-2-2-2-4-4-4-2-2-21234

2

Step-by-step solution

To solve this problem, we'll determine which graph represents the line given by y=(x+2)2 y=(x+2)^2 .

  • Step 1: The y-intercept for the function y=x+2 y = x + 2 is at point (0,2)(0, 2).

  • Step 2: Another point can be found by substituting x=4 x = -4 , giving y=4+2=2 y = -4 + 2 = -2 , so point (4,2)(-4, -2).

  • Step 3: Based on these points, we identify a slope of 2(2)0(4)=1 \frac{2 - (-2)}{0 - (-4)} = 1 .

  • Step 4: Check each graph to find the one that includes these details: y-intercept at 2 and another point at (4,2)(-4, -2).

Upon examining each option, we find that the graph matching these points and features corresponds to choice 3.

Thus, the correct graph is option 3.

3

Final Answer

3

Practice Quiz

Test your knowledge with interactive questions

Find the intersection of the function

\( y=(x+4)^2 \)

With the Y

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