Given the expression of the quadratic function
Finding the symmetry point of the function
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Given the expression of the quadratic function
Finding the symmetry point of the function
To solve this problem, we need to find the symmetry point of the quadratic function given by .
Thus, the symmetry point (also the vertex of the parabola) is .
Therefore, the solution to the problem is .
Given the expression of the quadratic function
The symmetrical axis of the expression must be found.
\( f(x)=-3x^2+3 \)
The symmetry point is the vertex of the parabola - the point where the graph is perfectly balanced! For , it's the lowest point at (0,3) where the parabola turns around.
In the standard form , our function has no x term. That means the coefficient of x is 0, so b = 0!
Think of it as "negative b over 2a" - it finds the x-value exactly halfway between the parabola's roots. When b = 0, the vertex sits right on the y-axis at x = 0.
Remember: (x,y) means "go right x units, then up y units". For (0,3), you don't move horizontally (x=0) but go up 3 units (y=3). Think "x comes first, y comes second"!
Yes! Every quadratic function has exactly one vertex, which is its symmetry point. The parabola is perfectly symmetric - if you fold it along the vertical line through the vertex, both sides match perfectly.
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