Locate the Symmetry Point of the Quadratic Function f(x)=3+3x^2

Quadratic Functions with Vertex Form

Given the expression of the quadratic function

Finding the symmetry point of the function

f(x)=3+3x2 f(x)=3+3x^2

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find the point of symmetry in the function
00:03 Point of symmetry is the point where if you fold the parabola in half
00:06 The halves will be equal to each other
00:11 Let's examine the function's coefficients
00:22 We'll use the formula to calculate the vertex point
00:25 We'll substitute appropriate values according to the given data and solve for X at the point
00:30 This is the X value at the point of symmetry
00:33 Now let's substitute this X value in the function to find the Y value at the point
00:42 This is the Y value at the point of symmetry
00:48 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Given the expression of the quadratic function

Finding the symmetry point of the function

f(x)=3+3x2 f(x)=3+3x^2

2

Step-by-step solution

To solve this problem, we need to find the symmetry point of the quadratic function given by f(x)=3+3x2 f(x) = 3 + 3x^2 .

  • Step 1: Identify the type of quadratic equation. Here, it's ax2+bx+c ax^2 + bx + c where a=3 a = 3 , b=0 b = 0 , and c=3 c = 3 .
  • Step 2: Use the formula for the symmetry point x=b2a x = -\frac{b}{2a} . Since b=0 b = 0 , the formula simplifies to x=0 x = 0 .
  • Step 3: Calculate the y-coordinate by substituting x=0 x = 0 into the original function: f(0)=3(0)2+3=3 f(0) = 3(0)^2 + 3 = 3 .

Thus, the symmetry point (also the vertex of the parabola) is (0,3) (0, 3) .

Therefore, the solution to the problem is (0,3) (0, 3) .

3

Final Answer

(0,3) (0,3)

Key Points to Remember

Essential concepts to master this topic
  • Symmetry Point: The vertex of a parabola is its symmetry point
  • Formula: Use x=b2a x = -\frac{b}{2a} to find x-coordinate of vertex
  • Check: Substitute x-value back: f(0) = 3 + 3(0)² = 3 gives point (0,3) ✓

Common Mistakes

Avoid these frequent errors
  • Confusing coordinates and writing (3,0) instead of (0,3)
    Don't swap the x and y coordinates = wrong point location! Students often mix up which value goes first in the ordered pair. Always remember (x,y) format: x-coordinate first, then y-coordinate.

Practice Quiz

Test your knowledge with interactive questions

Given the expression of the quadratic function

The symmetrical axis of the expression must be found.

\( f(x)=-3x^2+3 \)

FAQ

Everything you need to know about this question

What exactly is a symmetry point in a quadratic function?

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The symmetry point is the vertex of the parabola - the point where the graph is perfectly balanced! For f(x)=3+3x2 f(x) = 3 + 3x^2 , it's the lowest point at (0,3) where the parabola turns around.

Why is b = 0 in this function?

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In the standard form ax2+bx+c ax^2 + bx + c , our function f(x)=3+3x2 f(x) = 3 + 3x^2 has no x term. That means the coefficient of x is 0, so b = 0!

How do I remember the vertex formula?

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Think of it as "negative b over 2a" - it finds the x-value exactly halfway between the parabola's roots. When b = 0, the vertex sits right on the y-axis at x = 0.

What if I get confused about which coordinate is which?

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Remember: (x,y) means "go right x units, then up y units". For (0,3), you don't move horizontally (x=0) but go up 3 units (y=3). Think "x comes first, y comes second"!

Does every parabola have exactly one symmetry point?

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Yes! Every quadratic function has exactly one vertex, which is its symmetry point. The parabola is perfectly symmetric - if you fold it along the vertical line through the vertex, both sides match perfectly.

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