Given the expression of the quadratic function
Finding the symmetry point of the function
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Given the expression of the quadratic function
Finding the symmetry point of the function
To solve this problem, we'll follow these steps:
Now, let's work through each step:
Step 1: The function is given as . We have , , and .
Step 2: Using the formula , substitute and :
Step 3: Substitute back into the quadratic function to find the y-coordinate:
So, the vertex, or symmetry point, of the function is .
Therefore, the solution to the problem is .
Given the expression of the quadratic function
Finding the symmetry point of the function
\( f(x)=-5x^2+10 \)
The vertex is a point with coordinates like (0,12), while the axis of symmetry is a vertical line like x = 0. The vertex sits ON the axis of symmetry!
In , there's no x term (no linear term). This means b = 0 in the standard form .
Look at the coefficient of ! Since a = -3 is negative, the parabola opens downward, so the vertex (0,12) is the maximum point.
Then your answer would be x = 0 (the vertical line), not the point (0,12). Always read carefully to see if they want the line or the point!
Yes! Since , you can see the vertex is (0,12) directly from vertex form.
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