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To solve this problem, we'll follow these steps:
Let's go through the steps in detail:
Step 1: The dividend is and the divisor is . Our task is to perform long division.
Step 2: Start from the leftmost digit of the dividend:
Step 3: Bring down the next digit, , making the new number .
Step 4: Bring down the next digit, , making the new number .
The long division is complete. We are left with:
Thus, the division shows that with a remainder of .
Therefore, the solution to the problem is with a remainder of .
with a remainder of 1
Look at the first two digits together! Since 2 < 5, we use 24 instead. This gives us 24 ÷ 5 = 4 remainder 4 to start our division.
Write each quotient digit directly above the last digit you used from the dividend. For 24 ÷ 5 = 4, write the 4 above the second digit (the 4 in 24).
That means you made an error! The remainder must always be smaller than the divisor. If your remainder is 5 or bigger when dividing by 5, you need a larger quotient digit.
Bringing down one digit at a time keeps the numbers manageable and follows the systematic process of long division. It ensures we don't skip steps or make calculation errors.
Use the division check formula: Dividend = Divisor × Quotient + Remainder. For our problem: ✓
The remainder is what's left over after division. In remainder 1, it means 2436 has 487 complete groups of 5, plus 1 extra.
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