Long Division Problem: Dividing 133 by 7 Step-by-Step

Video Solution

Solution Steps

00:00 Solve

00:03 Let's start by dividing the leftmost digit in the dividend

00:08 7 is greater than 1, so we'll bring down the next digit and then divide

00:14 Write the result without remainder above, paying attention to position

00:20 Now multiply the result by the divisor

00:25 Subtract the product from the number

00:30 Now bring down the next digit below and use the same steps

00:36 Divide

00:39 Write the result above

00:43 Multiply the result, subtract

00:48 We got a remainder of 0

00:51 And this is the solution to the problem

Step-by-Step Solution

To solve this problem, we'll perform long division:

**Step 1**: Write down the division as $133 \div 7$ .
**Step 2**: Start with the leading digit or first two digits, $13$ . Determine how many times 7 can fit into 13. The number 7 fits into 13 a total of 1 time.
**Step 3**: Multiply 1 by 7 to get 7, and subtract 7 from 13 to get a remainder of 6.
**Step 4**: Bring down the next digit, which is 3, making the number 63.
**Step 5**: Determine how many times 7 can fit into 63. The number 7 fits into 63 a total of 9 times.
**Step 6**: Multiply 9 by 7 to get 63. Subtract 63 from 63 to obtain a remainder of 0.

Therefore, the division results in $19$ with no remainder.

The solution to the problem is $19$ .