The graph of the function below intersects the-axis at points A and B.
The vertex of the parabola is marked at point C.
Find all values of where.
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The graph of the function below intersects the-axis at points A and B.
The vertex of the parabola is marked at point C.
Find all values of where.
To solve this problem, let's analyze the graph of the quadratic function around points A and B where it intersects the -axis.
The solution, therefore, is found within the interval between the intercepts on an upward-opening parabola. This conclusion is consistent with the graphical representation of most standard quadratics.
Thus, the values of where are precisely in the interval .
The graph of the function below does not intersect the \( x \)-axis.
The parabola's vertex is marked A.
Find all values of \( x \) where
\( f\left(x\right) > 0 \).
Look at the vertex position! In this graph, vertex C is below the x-axis, and the parabola curves upward from there. An upward-opening parabola has its vertex at the lowest point.
Because the parabola is below the x-axis between the roots! When a graph is below the x-axis, the y-values (function values) are negative. Between A and B, the parabola dips down below zero.
Great thinking! If you test a point like x = 0 (assuming it's outside A and B), you'll find f(0) > 0, confirming the function is positive outside the roots and negative between them.
The vertex helps you visualize the parabola's shape, but what matters most are the roots A and B. The function is negative between the roots regardless of where exactly the vertex is located.
Yes! If you can determine the x-coordinates of points A and B from the graph, you can write something like instead of .
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