Perfect Square Expansion: Find the Missing Term in x² + ? + 9 = (x-3)²

Question

Fill in the blanks:

x2+?+9=(x3)2 x^2+?+9=(x-3)^2

Video Solution

Solution Steps

00:00 Complete the missing
00:03 We'll use shortened multiplication formulas to open the parentheses
00:13 We'll solve the multiplication
00:18 We'll identify what's missing and complete it
00:21 And this is the solution to the question

Step-by-Step Solution

To address this mathematical problem, we will apply the square of a binomial formula and solve for the missing term. Here's how:

  • Step 1: Expand the right-hand side of the equation (x3)2(x-3)^2.
  • Step 2: Equate the expanded form to x2+?+9x^2 + ? + 9.
  • Step 3: Solve for the missing term by comparing the coefficients.

Step 1: Expanding (x3)2(x-3)^2 using the formula, we get:

(x3)2=x22x3+32 (x - 3)^2 = x^2 - 2 \cdot x \cdot 3 + 3^2 .

This simplifies to:

x26x+9 x^2 - 6x + 9 .

Step 2: Equating this to the left-hand side:

x2+?+9=x26x+9 x^2 + ? + 9 = x^2 - 6x + 9 .

Step 3: Compare the terms:

The term that replaces "?" on the left-hand side must make the equation hold.

Setting corresponding terms equal, we find that:

?=6x ? = -6x .

Therefore, the solution to the problem is 6x -6x .

Answer

6x -6x