Perfect Square Expansion: Complete (2x-?)² = 4x²-12x+?

Question

Fill in the blanks:

(2x?)2=4x212x+? (2x-?)^2=4x^2-12x+\text{?}

Video Solution

Solution Steps

00:00 Complete the missing
00:03 Use the shortened multiplication formulas to open the parentheses
00:06 Let's mark A as the unknown
00:14 Calculate the square and multiplication
00:26 Compare the equal parts and solve for A
00:35 Isolate A
00:47 This is our unknown A
00:51 Substitute the solution for A in the correct places
00:55 Calculate 3 squared and substitute
00:59 And this is the solution to the question

Step-by-Step Solution

To solve the problem, we'll follow these steps:

  • Step 1: Identify the given form and match it with the square of a difference formula
  • Step 2: Determine the values of 'a' and 'b' such that the expanded form matches both sides of the equation
  • Step 3: Calculate the missing value in the expression

Now, let's work through each step:
Step 1: We are given the expression (2x?)2=4x212x+? (2x-?)^2=4x^2-12x+\text{?} .
Step 2: Using the standard formula for a perfect square expansion:
(2xb)2=(2x)222xb+b2=4x24xb+b2(2x-b)^2 = (2x)^2 - 2 \cdot 2x \cdot b + b^2 = 4x^2 - 4xb + b^2.
By matching coefficients, in 4x212x+?4x^2 - 12x + \text{?}, we see 4xb=12x4xb = 12x. Thus, b=3b = 3.
Step 3: Substitute b=3b = 3 into b2b^2 to get the constant term: b2=32=9b^2 = 3^2 = 9.

Therefore, the solution to the problem is 3, 93,\text{ }9.

Answer

3, 9 3,\text{ }9