Place Value Puzzle: Finding the Number 246 Using Digit Positions

Place Value Construction with Three-Digit Numbers

My hundreds digit is 2, my tens digit is 4 and my units digit is 6.


Which number am I?

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Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

My hundreds digit is 2, my tens digit is 4 and my units digit is 6.


Which number am I?

2

Step-by-step solution

To solve this problem, we'll construct the number using its digits based on their positional value:

  • The hundreds digit is 2, giving 2×100=200 2 \times 100 = 200 .
  • The tens digit is 4, giving 4×10=40 4 \times 10 = 40 .
  • The units digit is 6, giving 6×1=6 6 \times 1 = 6 .

Now, sum the results to find the actual number:

200+40+6=246 200 + 40 + 6 = 246

Therefore, the number is 246 246 .

The correct choice from the options provided is 246 246 , which is choice 4.

3

Final Answer

246 246

Key Points to Remember

Essential concepts to master this topic
  • Place Value Rule: Each digit's position determines its actual value
  • Construction Method: Multiply each digit by its place value: 2×100 + 4×10 + 6×1
  • Verification: Check that 200 + 40 + 6 = 246 matches the given digits ✓

Common Mistakes

Avoid these frequent errors
  • Writing digits in wrong order
    Don't just write the digits 2, 4, 6 in any random order like 462 or 642! This ignores which position each digit belongs in. Always place each digit in its correct position: hundreds digit 2 goes first, tens digit 4 goes second, units digit 6 goes last.

Practice Quiz

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What number do the blue squares below represent?

FAQ

Everything you need to know about this question

What's the difference between digit and place value?

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A digit is just the symbol (like 2, 4, or 6), but place value tells us what that digit is worth based on its position. The digit 2 in the hundreds place is worth 200!

Why can't I just write 246 without doing the multiplication?

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You absolutely can! But understanding the why behind it helps you solve harder problems. Breaking it down as 2×100+4×10+6×1 2 \times 100 + 4 \times 10 + 6 \times 1 shows you understand place value.

What if the problem had a zero in one of the positions?

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Great question! If the tens digit was 0, you'd have something like 206. The zero contributes 0×10=0 0 \times 10 = 0 , so it doesn't add anything to the total.

How do I remember which position is which?

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Think of it from right to left: the rightmost digit is always units (ones), then tens, then hundreds. Or use the phrase 'Hundreds, Tens, Units' from left to right!

Can this method work for bigger numbers too?

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Absolutely! The same pattern continues: thousands place (×1000 \times 1000 ), ten-thousands place (×10000 \times 10000 ), and so on. Each position is 10 times bigger than the one to its right.

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