Given the rhombus:
Are the triangles formed by the diagonal congruent?
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Given the rhombus:
Are the triangles formed by the diagonal congruent?
To determine if the triangles formed by the diagonals of a rhombus are congruent, we proceed with the following analysis:
Step 1: Understanding the properties of a rhombus
Step 2: Applying congruency conditions
Consider the diagonals and that intersect at a point . The triangles of interest are , , , and .
Each diagonal is bisected by the other, meaning and . Because the diagonals intersect at right angles, each of these triangles is a right triangle.
By the Side-Side-Side (SSS) postulate of congruence:
Step 3: Conclusion
Thus, all four triangles , , , and are congruent by SSS postulate, confirming that the triangles formed by the intersection of the diagonals in a rhombus are congruent.
Therefore, the statement that the triangles formed by the diagonals of a rhombus are congruent is .
True
Do the diagonals of the rhombus above intersect each other?
Rhombus diagonals are unique because they bisect each other at right angles. This creates four right triangles with equal corresponding sides, making congruence easier to prove.
The diagonals create four triangles: , , , and where E is the intersection point. All four are congruent to each other!
A square is a special type of rhombus! The same diagonal properties apply - they still bisect each other at right angles, so the triangles are still congruent.
Yes! You could use SAS (two equal sides from rhombus + right angle) or even ASA if you identify the angles. SSS is often easiest because all sides are clearly equal.
No! You don't need specific measurements. The properties of a rhombus (all sides equal, diagonals bisect at right angles) are enough to prove congruence algebraically.
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