Rectangle ABCD is similar to Rectangle EFGH.
The ratio between the lengths of their sides is 9:8.
If we multiply the lengths of the sides by 9, then what is the ratio between the areas of the large rectangles?
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Rectangle ABCD is similar to Rectangle EFGH.
The ratio between the lengths of their sides is 9:8.
If we multiply the lengths of the sides by 9, then what is the ratio between the areas of the large rectangles?
We raise to the power of 2:
81:64
Because area is two-dimensional! When you scale a rectangle, both length and width change by the same factor. So if sides are 9:8, then areas are .
This is asking about the final step - after finding that areas are in ratio 81:64, the question asks what happens next. But the answer is still 81:64 because that's the area ratio of the similar rectangles.
Think about it this way: Length ratios → square for area, cube for volume. Area has 2 dimensions, so you raise the ratio to the 2nd power!
Yes! For any similar figures, if the side ratio is a:b, then the area ratio is always . This works for triangles, circles, polygons - everything!
Same process! Square the fraction: . You can write this as either 81:64 or .
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