Similar Rectangles: Finding Area Ratio with 9:8 Side Length Proportion

Area Scaling with Similar Rectangle Ratios

Rectangle ABCD is similar to Rectangle EFGH.

The ratio between the lengths of their sides is 9:8.

If we multiply the lengths of the sides by 9, then what is the ratio between the areas of the large rectangles?

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find the ratio of areas between the large rectangles
00:03 We multiplied the rectangles according to the given data
00:13 The ratio of rectangle areas equals the similarity ratio squared
00:33 Square both numerator and denominator
00:41 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Rectangle ABCD is similar to Rectangle EFGH.

The ratio between the lengths of their sides is 9:8.

If we multiply the lengths of the sides by 9, then what is the ratio between the areas of the large rectangles?

2

Step-by-step solution

We raise to the power of 2:

92:82=81:64 9^2:8^2=81:64

3

Final Answer

81:64

Key Points to Remember

Essential concepts to master this topic
  • Similarity Rule: Area ratio equals side ratio squared for similar figures
  • Technique: Square the side ratio: 92:82=81:64 9^2:8^2 = 81:64
  • Check: Area ratio should be larger than side ratio when ratio > 1 ✓

Common Mistakes

Avoid these frequent errors
  • Using side ratio directly for area ratio
    Don't use 9:8 as the area ratio = completely wrong answer! Area involves two dimensions (length × width), so the ratio gets multiplied by itself. Always square the side ratio to get the area ratio.

Practice Quiz

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FAQ

Everything you need to know about this question

Why do we square the ratio instead of just using 9:8?

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Because area is two-dimensional! When you scale a rectangle, both length and width change by the same factor. So if sides are 9:8, then areas are 9×9:8×8=81:64 9 \times 9 : 8 \times 8 = 81:64 .

What does 'multiply the lengths by 9' mean in the question?

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This is asking about the final step - after finding that areas are in ratio 81:64, the question asks what happens next. But the answer is still 81:64 because that's the area ratio of the similar rectangles.

How do I remember to square the ratio?

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Think about it this way: Length ratios → square for area, cube for volume. Area has 2 dimensions, so you raise the ratio to the 2nd power!

Would this work for any similar shapes?

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Yes! For any similar figures, if the side ratio is a:b, then the area ratio is always a2:b2 a^2:b^2 . This works for triangles, circles, polygons - everything!

What if the ratio was given as a fraction like 9/8?

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Same process! Square the fraction: (98)2=8164 \left(\frac{9}{8}\right)^2 = \frac{81}{64} . You can write this as either 81:64 or 8164 \frac{81}{64} .

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