Simplify (1/x - x)²: Square of Difference Expression

Squaring Binomials with Rational Terms

(1xx)2= (\frac{1}{x}-x)^2=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Simply
00:03 We'll use the shortened multiplication formulas to open the parentheses
00:12 In this case 1 divided by X is A
00:18 and X is B in the formula
00:22 Therefore, we'll substitute into the formula and solve
00:35 We'll make sure to square both numerator and denominator
00:41 We'll reduce what we can
00:55 We'll put all terms under a common denominator
01:00 We'll group like terms
01:10 We'll use the commutative law and arrange the exercise
01:17 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

(1xx)2= (\frac{1}{x}-x)^2=

2

Step-by-step solution

To solve this problem, we'll use the square of a binomial formula:

  • Identify a=1xa = \frac{1}{x} and b=xb = x.
  • Apply the formula (ab)2=a22ab+b2(a - b)^2 = a^2 - 2ab + b^2.
  • Simplify each component and obtain the final expression.

Let's work through the steps:

Step 1: Identify the components:
a=1x a = \frac{1}{x} , b=x b = x

Step 2: Apply the formula:

(1xx)2=(1x)22×1x×x+x2(\frac{1}{x} - x)^2 = (\frac{1}{x})^2 - 2 \times \frac{1}{x} \times x + x^2

Simplifying each term:

(1x)2=1x2(\frac{1}{x})^2 = \frac{1}{x^2}

2×1x×x=2-2 \times \frac{1}{x} \times x = -2

x2=x2x^2 = x^2

Step 3: Combine and simplify:

1x22+x2\frac{1}{x^2} - 2 + x^2

To combine these into a single fraction, find a common denominator x2x^2:

1x22x2x2+x4x2=12x2+x4x2\frac{1}{x^2} - \frac{2x^2}{x^2} + \frac{x^4}{x^2} = \frac{1 - 2x^2 + x^4}{x^2}

Thus, the simplified expression is:

x42x2+1x2\frac{x^4 - 2x^2 + 1}{x^2}

Comparing to the choices provided, the correct choice is:

Choice 3: x42x2+1x2\frac{x^4 - 2x^2 + 1}{x^2}

3

Final Answer

x42x2+1x2 \frac{x^4-2x^2+1}{x^2}

Key Points to Remember

Essential concepts to master this topic
  • Formula: Use (a - b)² = a² - 2ab + b² for squaring differences
  • Technique: Calculate (1x)2=1x2 (\frac{1}{x})^2 = \frac{1}{x^2} and 21xx=2 -2 \cdot \frac{1}{x} \cdot x = -2
  • Check: Verify common denominator x2 x^2 gives x42x2+1x2 \frac{x^4 - 2x^2 + 1}{x^2}

Common Mistakes

Avoid these frequent errors
  • Adding the middle term instead of subtracting
    Don't write (a - b)² = a² + 2ab + b² = wrong positive middle term! This formula only applies to (a + b)², not differences. Always use (a - b)² = a² - 2ab + b² with the negative middle term.

Practice Quiz

Test your knowledge with interactive questions

Declares the given expression as a sum

\( (7b-3x)^2 \)

FAQ

Everything you need to know about this question

Why can't I just square each term separately?

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Because (a - b)² ≠ a² - b²! When you square a binomial, you must include the middle term -2ab. The expansion formula ensures you capture all the cross-multiplication that happens.

How do I handle the fraction 1/x when squaring?

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Square both the numerator and denominator: (1x)2=12x2=1x2 (\frac{1}{x})^2 = \frac{1^2}{x^2} = \frac{1}{x^2} . Remember that squaring a fraction means squaring the top and bottom separately.

What's the easiest way to find the middle term?

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Use the formula -2ab where a = 1/x and b = x. So: 21xx=2 -2 \cdot \frac{1}{x} \cdot x = -2 because the x's cancel out!

How do I combine terms with different denominators?

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Find a common denominator! Here, use x2 x^2 : write 2=2x2x2 -2 = \frac{-2x^2}{x^2} and x2=x4x2 x^2 = \frac{x^4}{x^2} to combine everything.

Can this expression be factored further?

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Yes! Notice that x42x2+1=(x21)2 x^4 - 2x^2 + 1 = (x^2 - 1)^2 , so the final answer can also be written as (x21)2x2 \frac{(x^2 - 1)^2}{x^2} .

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