xA+2Bx=x(2x−3)2−c
Calculate the values of A, B, and C.
To solve this problem, we'll proceed with the following steps:
- Step 1: Expand the expression (2x−3)2 on the right-hand side.
- Step 2: Simplify the resulting expression by dividing by x.
- Step 3: Compare the terms on both sides of the equation to deduce the coefficients A, B, and C.
Now, let us work through these steps:
Step 1: Expand the expression (2x−3)2.
(2x−3)2=4x2−12x+9
Step 2: Substitute back into the equation and simplify by dividing by x:
xA+2Bx=x4x2−12x+9−C
This simplifies to:
4x−12+x9−C
Step 3: To find A, B, and C, compare coefficients of similar terms:
- Constant term (no x): Equate −12 with −C to get C=12 (note: should consider sign reversal).
- Coefficient of x: Compare 2B to 4. Giving B=8.
- Coefficient of x1: Compare A to 9, giving A=9.
Therefore, the solution to the problem is that the values are A = 9, B = 8, C = -12.
A=9,B=8,C=−12