Simplify the Expression: m²/9 - 4mn/3 + 4n² Step-by-Step

Perfect Square Trinomials with Fractional Terms

m2943mn+4n2=? \frac{m^2}{9}-\frac{4}{3}mn+4n^2=\text{?}

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Express as brackets
00:03 Break down 9 into 3 squared
00:11 Break down 4 into 2 squared
00:17 Extract root and square
00:29 Factor with 2 and 2
00:32 Extract root and square
00:49 Use shortened multiplication formulas to find the brackets
01:00 These are A and B
01:06 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

m2943mn+4n2=? \frac{m^2}{9}-\frac{4}{3}mn+4n^2=\text{?}

2

Step-by-step solution

To solve this problem, we'll simplify the expression m2943mn+4n2\frac{m^2}{9} - \frac{4}{3}mn + 4n^2 to reveal a possible square of a binomial:

  • Step 1: Recognize the expression m2943mn+4n2\frac{m^2}{9} - \frac{4}{3}mn + 4n^2 may have terms fitting the identity (ab)2=a22ab+b2(a - b)^2 = a^2 - 2ab + b^2.
  • Step 2: Identify parts of the expression:
    - a2=m29a^2 = \frac{m^2}{9}, so a=m3a = \frac{m}{3}.
    - 2ab=43mn-2ab = -\frac{4}{3}mn. Since a=m3a = \frac{m}{3}, solve for bb:
    2×m3×b=43mn2b=4nb=2n2 \times \frac{m}{3} \times b = \frac{4}{3}mn \Rightarrow 2b = 4n \Rightarrow b = 2n.
  • Step 3: Check b2b^2: b2=(2n)2=4n2b^2 = (2n)^2 = 4n^2, which matches the 4n24n^2 term in the expression.

Therefore, the correct form of the expression is:
(m32n)2(\frac{m}{3} - 2n)^2.

Thus, the expression simplifies to:

(m32n)2 (\frac{m}{3} - 2n)^2

3

Final Answer

(m32n)2 (\frac{m}{3}-2n)^2

Key Points to Remember

Essential concepts to master this topic
  • Pattern Recognition: Look for a22ab+b2=(ab)2 a^2 - 2ab + b^2 = (a-b)^2 structure
  • Technique: From m29 \frac{m^2}{9} , identify a=m3 a = \frac{m}{3} for the first term
  • Check: Expand (m32n)2 (\frac{m}{3} - 2n)^2 to verify it equals original expression ✓

Common Mistakes

Avoid these frequent errors
  • Incorrectly identifying the perfect square pattern
    Don't assume any trinomial is a perfect square without checking all three terms! Students often guess patterns and get expressions like (m94n)2 (\frac{m}{9} - 4n)^2 which expand incorrectly. Always verify by identifying a a from the first term, then check if 2ab -2ab and b2 b^2 match exactly.

Practice Quiz

Test your knowledge with interactive questions

Declares the given expression as a sum

\( (7b-3x)^2 \)

FAQ

Everything you need to know about this question

How do I know if this is a perfect square trinomial?

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Look for the pattern a22ab+b2 a^2 - 2ab + b^2 . If the first and last terms are perfect squares and the middle term is exactly twice their product, then it factors as (ab)2 (a-b)^2 .

Why is a = m/3 and not something else?

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Since the first term is m29 \frac{m^2}{9} , we need a2=m29 a^2 = \frac{m^2}{9} . Taking the square root: a=m3 a = \frac{m}{3} . This is the only value that works!

How do I find b from the middle term?

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The middle term is 4mn3 -\frac{4mn}{3} , which should equal 2ab -2ab . Since a=m3 a = \frac{m}{3} , we get: 2m3b=4mn3 -2 \cdot \frac{m}{3} \cdot b = -\frac{4mn}{3} , so b = 2n.

What if I can't see the perfect square pattern?

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Try working backwards! Look at each answer choice and expand them to see which one gives you the original expression. This helps you understand the pattern better.

Do I always get a perfect square with three terms?

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No! Not all trinomials are perfect squares. Always check that the pattern a2±2ab+b2 a^2 ± 2ab + b^2 matches exactly before factoring as (a±b)2 (a ± b)^2 .

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