Simplify the Nested Radical: ∛(√(64x¹²))

Nested Radicals with Multiple Operations

Complete the following exercise:

64x12=3 \sqrt[3]{\sqrt{64\cdot x^{12}}=}

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Solve the following problem
00:03 A "regular" root is of the order 2
00:08 When we have a number (A) to the power of (B) in a root of order (C)
00:13 The result equals the number (A) to the power of their product (B times C)
00:17 We'll apply this formula to our exercise, and proceed to calculate the product of the orders
00:31 When we have a root of a product (A times B)
00:36 We can write it as a product of the root of each term
00:39 We'll apply this formula to our exercise, and break down the root
00:44 Break down 64 to 2 to the power of 6
00:50 When we have a number (A) to the power of (B) in a root of order (C)
00:55 The result equals number (A) to the power of their quotient (B divided by C)
01:01 We'll apply this formula to our exercise, and proceed to calculate the quotient of powers
01:11 This is the solution

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Complete the following exercise:

64x12=3 \sqrt[3]{\sqrt{64\cdot x^{12}}=}

2

Step-by-step solution

To solve the problem 64x123 \sqrt[3]{\sqrt{64 \cdot x^{12}}} , follow these detailed steps:

  • Step 1: Simplify the inner expression.
    The expression inside the radical is 64x12 64 \cdot x^{12} .
  • Step 2: Simplify the inner square root.

    First, we need to find 64x12 \sqrt{64 \cdot x^{12}} .

    The square root of a product can be expressed as the product of the square roots: 64x12 \sqrt{64} \cdot \sqrt{x^{12}} .

    Simplifying further, we find:

    • 64=8 \sqrt{64} = 8 , since 82=64 8^2 = 64 .
    • x12=x6 \sqrt{x^{12}} = x^{6} , because (x6)2=x12 (x^{6})^2 = x^{12} .

    Thus, the inner square root becomes 8x6 8x^6 .

  • Step 3: Simplify using the cube root.

    Next, apply the cube root to the result of the inner square root: 8x63 \sqrt[3]{8x^6} .

    The cube root of a product can also be expressed as the product of the cube roots:

    • 83=2 \sqrt[3]{8} = 2 , since 23=8 2^3 = 8 .
    • x63=x6/3=x2 \sqrt[3]{x^6} = x^{6/3} = x^{2} , because (x2)3=x6 (x^2)^3 = x^6 .

    Thus, the expression simplifies to 2x2 2x^2 .

Therefore, the solution to this problem is 2x2 2x^2 , which corresponds to choice 2 in the provided options.

3

Final Answer

2x2 2x^2

Key Points to Remember

Essential concepts to master this topic
  • Rule: Simplify from innermost radical outward systematically
  • Technique: 64x12=8x6 \sqrt{64x^{12}} = 8x^6 before applying cube root
  • Check: Verify (2x2)3=8x6 (2x^2)^3 = 8x^6 and (8x6)2=64x12 (8x^6)^2 = 64x^{12}

Common Mistakes

Avoid these frequent errors
  • Trying to combine radicals before simplifying inner expressions
    Don't write 64x126 \sqrt[6]{64x^{12}} immediately = skips crucial steps! This makes the problem much harder and often leads to calculation errors. Always simplify the innermost radical first, then work outward step by step.

Practice Quiz

Test your knowledge with interactive questions

Solve the following exercise:

\( \sqrt[10]{\sqrt[10]{1}}= \)

FAQ

Everything you need to know about this question

Why can't I just make this into one radical with index 6?

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While a3=a6 \sqrt[3]{\sqrt{a}} = \sqrt[6]{a} is mathematically correct, it's much easier to simplify step by step. Working from inside out helps you spot perfect squares and cubes more easily!

How do I know that √64 = 8 and not -8?

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The radical symbol \sqrt{} always means the positive square root by convention. So 64=8 \sqrt{64} = 8 , even though both 8² and (-8)² equal 64.

Why is √(x¹²) = x⁶ and not x⁶ with absolute value bars?

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You're right to think about this! If we need to be completely rigorous, it should be x6 |x^6| . However, in most algebra contexts, we assume variables represent values that make the expression defined and real.

What if I get confused about which exponent rule to use?

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Remember: xmn=xm/n \sqrt[n]{x^m} = x^{m/n} . So x12=x12/2=x6 \sqrt{x^{12}} = x^{12/2} = x^6 and x63=x6/3=x2 \sqrt[3]{x^6} = x^{6/3} = x^2 . Divide the exponent by the radical index!

How can I check my final answer?

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Work backwards! If your answer is 2x2 2x^2 , then (2x2)3=8x6 (2x^2)^3 = 8x^6 and (8x6)2=64x12 (8x^6)^2 = 64x^{12} . This should match your original expression inside the radicals!

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