When we encounter an exercise in which there is a root applied to another root, we will multiply the order of the first root by the order of the second and the order obtained (the product of both) will be raised as a root in our number (as generally power of a power)
Let's put it this way:
Solve the following exercise:
\( \sqrt{\sqrt{2}}= \)
If you are interested in this article, you may also be interested in the following articles:
Laws of Radicals
The Root of a Product
Root of the Quotient
Combining Powers and Roots
In the blog of Tutorela you will find a variety of articles about mathematics.
Solve the following exercise:
\( \sqrt[5]{\sqrt[3]{5}}= \)
Solve the following exercise:
\( \sqrt[10]{\sqrt[10]{1}}= \)
Solve the following exercise:
\( \sqrt[6]{\sqrt{2}}= \)
