Solve (12-15÷3×2)/(10÷(2+3)): Order of Operations Challenge

Question

1215:3210:(2+3)= \frac{12-15:3\cdot2}{10:(2+3)}=

Video Solution

Solution Steps

00:13 Let's solve this expression together.
00:16 First, break it down into the top and bottom parts.
00:20 Remember, we do multiplication and division before addition and subtraction.
00:26 Also, work from left to right as you go.
00:29 And always start with what's inside the parentheses.
00:39 Keep focusing on multiplication and division first. Almost there!
00:49 And that gives us the final answer.

Step-by-Step Solution

We start by solving the exercise in the numerator and then solve the exercise in the denominator.

We know that multiplication and division operations come before addition and subtraction operations, so first we will divide 15:3 and then multiply the result by 2:

15:3=5 15:3=5

125×2=1210=2 12-5\times2=12-10=2

The result of the numerator is 2 and now we will solve the exercise that appears in the denominator.

It is known that according to the rules of the order of operations, the exercise that appears between parentheses goes first, so we first solve the exercise2+3=5 2+3=5

Now, we solve the division exercise:10:5=2 10:5=2

The result we get in the denominator is 2.

Finally, divide the numerator by the denominator:

22=1 \frac{2}{2}=1

Answer

1