Solve (-2)²)²: Double Square of a Negative Number

((2)2)2= ((-2)^2)^2=

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Step-by-step video solution

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00:00 Solve
00:03 We'll break down the exponent into multiplications, and solve
00:08 Negative times negative is always positive
00:22 We'll break down the exponent into multiplications, and solve
00:26 And this is the solution to the question

Step-by-step written solution

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1

Understand the problem

((2)2)2= ((-2)^2)^2=

2

Step-by-step solution

To solve the given problem, we'll use rules of exponents and follow these steps:

  • Step 1: Calculate the inner power. Simplify (2)2(-2)^2.
  • Step 2: Calculate the result by taking the square of the previous result.

Here's the detailed breakdown:


Step 1: Determine (2)2(-2)^2.
Using the property of exponents, (2)2=(2)×(2)=4(-2)^2 = (-2) \times (-2) = 4.

Step 2: Now, square the result from Step 1.
You are to calculate 424^2.
42=4×4=164^2 = 4 \times 4 = 16.

Therefore, the solution to the problem is 16\boxed{16}.

3

Final Answer

16 16

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\( (-2)^7= \)

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