Solve 3m(? + ?) = 6mn + 9m: Finding Missing Values in Algebraic Distribution

Fill in the missing values:

3m(?+?)=6mn+9m 3m(?+?)=6mn+9m

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Complete the missing values
00:03 Let's factor 6 into 3×2
00:10 Let's factor 9 into 3 and 3
00:25 Let's mark the common factors
00:29 Let's take out the common factors from the parentheses
00:39 And this is the solution to the question

Step-by-step written solution

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1

Understand the problem

Fill in the missing values:

3m(?+?)=6mn+9m 3m(?+?)=6mn+9m

2

Step-by-step solution

To solve this problem, we'll follow these steps:

  • Step 1: Look at the right side of the equation, 6mn+9m 6mn + 9m , and factor out the common term 3m 3m .
  • Step 2: Upon factoring, rewrite the expression as 3m(2n+3) 3m(2n + 3) .
  • Step 3: Compare this factored form to the left side 3m(?+?) 3m(?+?) .
  • Step 4: Identify the terms inside the parentheses: 2n 2n for the first place and 3 3 for the second.

Following these steps:
Step 1: Recognize that both terms 6mn 6mn and 9m 9m on the right have a common factor of 3m 3m .
Step 2: Factor out 3m 3m to get 3m(2n+3) 3m(2n + 3) .
Step 3: Note that 3m(?+?) 3m(?+?) needs to match 3m(2n+3) 3m(2n + 3) .
Step 4: Thus, the expressions inside the parentheses are ?=2n ? = 2n and ?=3 ? = 3 .

Therefore, the solution to the problem is 2n,3 2n, 3 .

3

Final Answer

2n,3 2n,3

Practice Quiz

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Break down the expression into basic terms:

\( 4x^2 + 6x \)

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