Solve for Missing Values in 12ab(? + ?) = 24abc + 36

Fill in the missing values:

12ab(?+?)=24abc+36 12ab(?+?)=24abc+36

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Complete the missing values
00:03 Factorize 24 into factors 12 and 2
00:08 Factorize 36 into factors 12 and 3
00:15 Multiply by the appropriate whole fraction
00:24 Mark the common factors
00:43 Take out the common factors from the parentheses
00:51 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Fill in the missing values:

12ab(?+?)=24abc+36 12ab(?+?)=24abc+36

2

Step-by-step solution

To solve this problem, we'll rewrite the expression 12ab(?+?)=24abc+36 12ab(?+?)=24abc+36 , focusing on the right-hand side, 24abc+36 24abc+36 .

Step 1: Factor the right-hand side:

Both terms on the right-hand side, 24abc 24abc and 36 36 , have a common factor. The greatest common factor (GCF) of 24abc 24abc and 36 36 is 12 12 . Therefore, we can factor out 12 12 :

24abc+36=12(2ac+3) 24abc + 36 = 12(2ac + 3) .

Step 2: Match the factored form with the left-hand side expression:

The equation now resembles 12ab(?+?)=12(2ac+3) 12ab(?+?) = 12(2ac + 3) . To make the left-hand side equivalent to this expression, we equate it to the factorization result:

12ab(?+?)=12×(2ac+3) 12ab(?+?) = 12 \times (2ac + 3) implies ab(?+?)=2ac+3 ab(?+?) = 2ac + 3 .

Step 3: Divide both sides by ab ab :

?+?=2acab+3ab=2c+3ab ? + ? = \frac{2ac}{ab} + \frac{3}{ab} = 2c + \frac{3}{ab} .

Therefore, the missing values in the expression are 2c 2c and 3ab \frac{3}{ab} .

Comparing this with the answer choices, the correct choice that aligns with these values is: 2c,3ab 2c, \frac{3}{ab} .

Therefore, the solution to the problem is 2c,3ab 2c, \frac{3}{ab} .

3

Final Answer

2c,3ab 2c,\frac{3}{ab}

Practice Quiz

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Break down the expression into basic terms:

\( 4x^2 + 6x \)

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