tutorela-logo TUTORELA
Learn math
Learn Math by Age
Practice Math
Practice Math by Grade
Blog About
Features
FAQ Terms of Service Privacy Policy
Login
Sign up

Solve (4+3)×(5-2): Order of Operations Practice

  • Home
  • Learn math
  • Solve (4+3)×(5-2): Order of Operations Practice

Question

(4+3)×(5−2)= (4+3)\times(5-2)= (4+3)×(5−2)=

Step-by-Step Solution

First, solve the expression inside the parentheses:

4+3=7 4+3=7 4+3=7

and

5−2=3 5-2=3 5−2=3

Thus, the equation becomes:

7×3 7\times3 7×3

Now, perform the multiplication:

7×3=21 7 \times 3 = 21 7×3=21.

Answer

21


More Questions

Parentheses in advanced Order of Operations

  • Solve 25 - (8 + 5): Order of Operations Practice
  • Solve the Expression: 20÷(4+1)-3 Using Order of Operations
  • Solve (8-3) × (2+4): Order of Operations Practice
  • Solve (50-10) × 2: Order of Operations Practice

Parentheses in simple Order of Operations

  • Solve the Expression: 30 - (10 + 7) Using Order of Operations
  • Solve 15-3×(2+1): Order of Operations Practice
  • Solve (12 + 8) ÷ 4: Order of Operations Practice
  • Solve: 9 × (2 × 1) Using Order of Operations

Related Subjects

Order of Operations with Parentheses Parentheses

Question Types

Parentheses in advanced Order of Operations: Addition, subtraction, multiplication and division Parentheses in simple Order of Operations: Addition, subtraction, multiplication and division
Tutorela
Pages
Home
About
Learn math
FAQ
Terms of Service
Privacy Policy
Notice to Tutor
Notice to Student
Contact Us: [email protected]