Solve (a×b×c)^(-2): Negative Exponent with Multiple Variables

To solve the equation $(a \times b \times c)^{-2}$, we'll make use of the exponent rules. The rule for a negative exponent states that $x^{-n} = \frac{1}{x^n}$. Therefore, applying this rule directly to our expression, we obtain:

$(a \times b \times c)^{-2} = \frac{1}{(a \times b \times c)^2}$.

Let's break this down step-by-step:

• Step 1: Recognize the need to convert the negative exponent. According to the exponent rule, any expression with a negative exponent can be rewritten as a reciprocal with a positive exponent.

• Step 2: Apply the rule: $(a \times b \times c)^{-2}$ becomes $\frac{1}{(a \times b \times c)^2}$.

By applying the rules correctly, we have simplified the expression to:

$\frac{1}{(a \times b \times c)^2}$.