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To solve this problem, we'll follow these steps:
We can begin with the addition:
Let's add each digit column by column:
Step 1: Add the units place (rightmost column).
The units are 7 and 3. Add these together: . Since 10 is more than 9, we place the 0 in the units place and carry over the 1 to the tens column.
Step 2: Add the tens place, including the carry from the previous step.
Now add the tens digits: . (The 1 is carried from the previous step, and 9 is the result.) Place 9 in the tens column.
Step 3: Add the hundreds place.
The hundreds place has a 9 with nothing to add, so it remains 9.
The resulting sum from the addition is 990. Therefore, the correct answer is:
Verifying with the given multiple-choice options, the correct answer is choice 3.
990
\( \begin{aligned} &12 \\ +& \\ &~~2 \\ &\underline{\phantom{776}} & \\ \end{aligned} \)
When two digits add up to 10 or more, you write down the ones digit and carry the tens digit to the next column. For example, 7 + 3 = 10, so write 0 and carry 1.
Place value alignment is crucial! The ones must line up with ones, tens with tens, etc. If 73 isn't properly aligned under 917, you'll add the wrong digits together.
Add all three numbers: the tens digit from the first number, the tens digit from the second number, AND the carried digit. So 1 + 7 + 1 (carried) = 9.
Treat missing digits as zero. In this problem, 73 has no hundreds digit, so it's like adding 917 + 073. The hundreds place becomes 9 + 0 = 9.
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