Solve: Evaluating -(-1)^100 with Double Negatives

When you raise -1 to an even power, the result is always positive 1! This happens because you're multiplying an even number of negative values: $(-1) \times (-1) \times ... \times (-1)$ = positive result.

The parentheses make a huge difference! $-(-1)^{100}$ means "negative of $(-1)^{100}$" which equals -1. But $(-(-1))^{100} = 1^{100} = 1$ because we simplify inside parentheses first.

Use PEMDAS! Exponents come before multiplication/division (including negation). So evaluate $(-1)^{100}$ first to get 1, then apply the outer negative sign.

Yes! If we had $-(-1)^{99}$, then $(-1)^{99} = -1$ (odd power), so $-(-1) = -(-1) = 1$. Even exponents give positive results, odd exponents keep the negative.

Never ignore parentheses! They're crucial for showing that the entire -1 is being raised to the 100th power. Without them, you might misinterpret the expression and get the wrong answer.