Solve for b: 4(b/2 + b) - 1/3 = 6b Linear Equation

Linear Equations with No Solution

4(b2+b)13=6b 4(\frac{b}{2}+b)-\frac{1}{3}=6b

b=? b=\text{?}

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Solve
00:04 Open parentheses properly, multiply by each factor
00:08 We want to isolate the variable B
00:16 Divide 4 by 2
00:28 Collect like terms
00:35 Arrange the equation so that only B is on one side
00:41 Simplify what we can
00:44 We got an illogical expression, therefore there is no solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

4(b2+b)13=6b 4(\frac{b}{2}+b)-\frac{1}{3}=6b

b=? b=\text{?}

2

Step-by-step solution

First, we'll expand the parentheses by multiplying each term by 4:

4×b2+4×b13=6b 4\times\frac{b}{2}+4\times b-\frac{1}{3}=6b

Let's then solve the multiplication exercise 4×b2=4b2=2b 4\times\frac{b}{2}=\frac{4b}{2}=2b .

Now the equation is:

2b+4b13=6b 2b+4b-\frac{1}{3}=6b

We can now combine the left-hand side between the two b b terms to get:

6b13=6b 6b-\frac{1}{3}=6b

We'll reduce both sides by 6b 6b , leaving us with:

13=0 -\frac{1}{3}=0

Since the result obtained is impossible, the exercise has no solution.

3

Final Answer

No solution

Key Points to Remember

Essential concepts to master this topic
  • Distribution Rule: Multiply each term inside parentheses by the outside coefficient
  • Technique: Combine like terms: 2b+4b=6b 2b + 4b = 6b
  • Check: When variables cancel and constants don't equal: no solution exists ✓

Common Mistakes

Avoid these frequent errors
  • Assuming every equation has a solution
    Don't keep solving when you get 13=0 -\frac{1}{3} = 0 = impossible statement! This contradictory result means the equation has no solution. Always recognize when variable terms cancel but constants don't match - this indicates no solution exists.

Practice Quiz

Test your knowledge with interactive questions

\( x+7=14 \)

\( x=\text{?} \)

FAQ

Everything you need to know about this question

How can an equation have no solution?

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When you simplify and get a false statement like 13=0 -\frac{1}{3} = 0 , it means there's no value of b that makes the original equation true. The equation is inconsistent!

What's the difference between no solution and zero as a solution?

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Zero as a solution means b = 0 works in the equation. No solution means no value (including zero) makes the equation true. Big difference!

Did I make a mistake if I get no solution?

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Not necessarily! Always double-check your algebra, but some equations genuinely have no solution. If your work is correct and you get a false statement, "no solution" is the right answer.

How do I distribute 4 to the fraction correctly?

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Multiply 4 by each term: 4×b2=4b2=2b 4 \times \frac{b}{2} = \frac{4b}{2} = 2b and 4×b=4b 4 \times b = 4b . Then combine: 2b+4b=6b 2b + 4b = 6b .

What should I write as my final answer?

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Write "No solution" or use the symbol \emptyset (empty set). Don't leave it blank or write "impossible" - be specific that no solution exists.

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