Solve for Missing Quantity: Maintaining 5:2 Ratio in Bakery Sales

In a bakery, the ratio between bread and cakes is 5:2 .
At the beginning of the day, there were 50 cakes in the bakery, of which 10 were sold.
At the end of the day, the ratio between bread and cakes remained the same.

How much bread was sold throughout the day?

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Step-by-step written solution

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1

Understand the problem

In a bakery, the ratio between bread and cakes is 5:2 .
At the beginning of the day, there were 50 cakes in the bakery, of which 10 were sold.
At the end of the day, the ratio between bread and cakes remained the same.

How much bread was sold throughout the day?

2

Step-by-step solution

To solve the problem, we'll follow these steps:

  • Step 1: Identify and apply the change in quantities based on sales.
  • Step 2: Set up an equation from the ratio and solve for bread.
  • Step 3: Calculate how much bread was sold.

Step 1:
At the beginning, there are 50 cakes in the bakery. After selling 10 cakes, the remaining cakes are 5010=40 50 - 10 = 40 .

Step 2:
At the end of the day, the ratio of bread to cakes remains 5:2. So for every 2 cakes, there are 5 loaves of bread.

If C C denotes the number of cakes after sales (which is 40), the number of bread B B is calculated based on the initial ratio:
B40=52\frac{B}{40} = \frac{5}{2}
Cross-multiplying gives:
B=40×52=100B = 40 \times \frac{5}{2} = 100

Step 3:
Initially, the number of cakes was 50 in correspondence to the same ratio, so initially:\)
b50=52\frac{b}{50} = \frac{5}{2}
Solving: b=50×52=125b = 50 \times \frac{5}{2} = 125

Thus, initially, there were 125 loaves of bread. At the end, there are 100 loaves, therefore the bread sold is:
125100=25125 - 100 = 25

Therefore, the solution to the problem is 25 25 .

3

Final Answer

25

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