Assuming the sequence continues according to the same rule, what number appears in the 11th element?
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Assuming the sequence continues according to the same rule, what number appears in the 11th element?
To solve this problem, we'll follow these steps:
Now, let's work through each step:
Step 1: The given sequence starts with 2, 5, 8. We determine the pattern by finding the difference between consecutive terms:
and so the common difference () is 3.
This indicates it is an arithmetic sequence with and .
Step 2: Use the arithmetic sequence formula to find the 11th term :
Substitute the known values:\
Therefore, the 11th element in the sequence is , which corresponds to choice
32
12 ☐ 10 ☐ 8 7 6 5 4 3 2 1
Which numbers are missing from the sequence so that the sequence has a term-to-term rule?
Check if the difference between consecutive terms is constant. Here: 5-2=3 and 8-5=3. Since the difference is always 3, it's arithmetic!
You can count up by the common difference! Start with 2, then add 3 ten more times: 2, 5, 8, 11, 14, 17, 20, 23, 26, 29, 32. The formula is just faster!
Because we start counting from the first term! To get from the 1st to the 11th term, we only add the common difference 10 times (11-1=10), not 11 times.
Absolutely! If the 11th term is 32, then the 10th term should be 32-3=29, the 9th term should be 29-3=26, and so on. This confirms your answer!
The method stays the same! Just use the new first term as in the formula. For example, if it started with 5, then instead of 2.
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