Solve for X: (2×7×21)/(5×6) Raised to Power X

Question

Insert the corresponding expression:

(2×7×215×6)x= \left(\frac{2\times7\times21}{5\times6}\right)^x=

Video Solution

Solution Steps

00:10 Let's simplify the problem step by step.
00:14 Remember, a fraction to the power of N, means both the top and bottom are raised to N.
00:20 So, each part of the fraction is raised to that power.
00:24 The top is a product, so we put it in parentheses.
00:28 Let's use this rule on our exercise now.
00:31 When a product is to the power of N, each part is raised separately to N.
00:36 This is important and makes things clearer.
00:40 Applying all these steps, we solve our exercise.
00:49 And that's how we find the solution. Well done!

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Understand the expression and the exponent rules.
  • Step 2: Apply the exponent to both the numerator and denominator.
  • Step 3: Simplify each part of the expression by distributing the exponent correctly.

Now, let's work through each step:
Step 1: The original expression is (2×7×215×6)x\left(\frac{2\times7\times21}{5\times6}\right)^x. It needs to be rewritten by applying the exponent to each part of the fraction according to the rules of exponents.
Step 2: Using (ab)x=axbx\left(\frac{a}{b}\right)^x = \frac{a^x}{b^x}, we apply the exponent xx to both the numerator and denominator:
(2×7×215×6)x=(2×7×21)x(5×6)x \left(\frac{2\times7\times21}{5\times6}\right)^x = \frac{(2\times7\times21)^x}{(5\times6)^x}
Step 3: Distribute the exponent xx across each multiplication in the numerator and the denominator according to the rule (a×b)x=ax×bx(a \times b)^x = a^x \times b^x:
In the numerator: (2×7×21)x=2x×7x×21x(2 \times 7 \times 21)^x = 2^x \times 7^x \times 21^x.
In the denominator: (5×6)x=5x×6x(5 \times 6)^x = 5^x \times 6^x.
Thus, the expression becomes:
2x×7x×21x5x×6x \frac{2^x \times 7^x \times 21^x}{5^x \times 6^x}

Therefore, the solution to the problem is 2x×7x×21x5x×6x\frac{2^x\times7^x\times21^x}{5^x\times6^x}.

Answer

2x×7x×21x5x×6x \frac{2^x\times7^x\times21^x}{5^x\times6^x}