Solve for X: (2×7×21)/(5×6) Raised to Power X

Exponent Rules with Fractional Expressions

Insert the corresponding expression:

(2×7×215×6)x= \left(\frac{2\times7\times21}{5\times6}\right)^x=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:10 Let's simplify the problem step by step.
00:14 Remember, a fraction to the power of N, means both the top and bottom are raised to N.
00:20 So, each part of the fraction is raised to that power.
00:24 The top is a product, so we put it in parentheses.
00:28 Let's use this rule on our exercise now.
00:31 When a product is to the power of N, each part is raised separately to N.
00:36 This is important and makes things clearer.
00:40 Applying all these steps, we solve our exercise.
00:49 And that's how we find the solution. Well done!

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Insert the corresponding expression:

(2×7×215×6)x= \left(\frac{2\times7\times21}{5\times6}\right)^x=

2

Step-by-step solution

To solve this problem, we'll follow these steps:

  • Step 1: Understand the expression and the exponent rules.
  • Step 2: Apply the exponent to both the numerator and denominator.
  • Step 3: Simplify each part of the expression by distributing the exponent correctly.

Now, let's work through each step:
Step 1: The original expression is (2×7×215×6)x\left(\frac{2\times7\times21}{5\times6}\right)^x. It needs to be rewritten by applying the exponent to each part of the fraction according to the rules of exponents.
Step 2: Using (ab)x=axbx\left(\frac{a}{b}\right)^x = \frac{a^x}{b^x}, we apply the exponent xx to both the numerator and denominator:
(2×7×215×6)x=(2×7×21)x(5×6)x \left(\frac{2\times7\times21}{5\times6}\right)^x = \frac{(2\times7\times21)^x}{(5\times6)^x}
Step 3: Distribute the exponent xx across each multiplication in the numerator and the denominator according to the rule (a×b)x=ax×bx(a \times b)^x = a^x \times b^x:
In the numerator: (2×7×21)x=2x×7x×21x(2 \times 7 \times 21)^x = 2^x \times 7^x \times 21^x.
In the denominator: (5×6)x=5x×6x(5 \times 6)^x = 5^x \times 6^x.
Thus, the expression becomes:
2x×7x×21x5x×6x \frac{2^x \times 7^x \times 21^x}{5^x \times 6^x}

Therefore, the solution to the problem is 2x×7x×21x5x×6x\frac{2^x\times7^x\times21^x}{5^x\times6^x}.

3

Final Answer

2x×7x×21x5x×6x \frac{2^x\times7^x\times21^x}{5^x\times6^x}

Key Points to Remember

Essential concepts to master this topic
  • Power Rule: Apply exponent to both numerator and denominator separately
  • Distribution: (a×b)x=ax×bx (a \times b)^x = a^x \times b^x for each factor
  • Check: Every factor gets the exponent: 2x,7x,21x,5x,6x 2^x, 7^x, 21^x, 5^x, 6^x

Common Mistakes

Avoid these frequent errors
  • Applying exponent to only some factors
    Don't apply x to just one number like 2×7×21x5×6 \frac{2 \times 7 \times 21^x}{5 \times 6} = incomplete distribution! This violates exponent rules and gives wrong results. Always apply the exponent to every single factor when distributing across multiplication.

Practice Quiz

Test your knowledge with interactive questions

\( 112^0=\text{?} \)

FAQ

Everything you need to know about this question

Why can't I just put the exponent on the whole fraction?

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You can keep it as (2×7×215×6)x \left(\frac{2\times7\times21}{5\times6}\right)^x , but the question asks you to distribute the exponent. This means breaking it down using exponent rules to show each factor raised to the power.

Do I need to calculate the numbers first before applying the exponent?

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No! Keep each factor separate with its own exponent. Don't calculate 2×7×21=294 2\times7\times21 = 294 first. The goal is to show the distributed form with individual exponents.

What's the difference between the numerator and denominator steps?

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Both follow the same rule! In the numerator: (2×7×21)x=2x×7x×21x (2\times7\times21)^x = 2^x\times7^x\times21^x . In the denominator: (5×6)x=5x×6x (5\times6)^x = 5^x\times6^x . Each multiplication becomes separate factors with exponents.

Why do all the wrong answers forget some exponents?

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Common mistakes include applying x x to only part of the expression. Remember: when you have (a×b×c)x (a\times b\times c)^x , every single factor must get the exponent!

How do I remember the exponent distribution rule?

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Think: "Every factor gets its own copy of the exponent." Just like (2×3)2=22×32=4×9=36 (2\times3)^2 = 2^2\times3^2 = 4\times9 = 36 , each number multiplied together needs the exponent applied to it individually.

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