Solve: (2×4×6)/(7×8×9) Raised to Power 3x

Insert the corresponding expression:

(2×4×67×8×9)3x= \left(\frac{2\times4\times6}{7\times8\times9}\right)^{3x}=

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1

Understand the problem

Insert the corresponding expression:

(2×4×67×8×9)3x= \left(\frac{2\times4\times6}{7\times8\times9}\right)^{3x}=

2

Step-by-step solution

Let's analyze the expression we are given:

(2×4×67×8×9)3x \left(\frac{2\times4\times6}{7\times8\times9}\right)^{3x}

The expression is a power of a fraction. The rule for powers of a fraction is that each component of the fraction must be raised to the power separately. This can be expressed as:

(ab)n=anbn \left(\frac{a}{b}\right)^n = \frac{a^n}{b^n}

Applying this rule to our expression, we have:

  • The numerator inside the power: 2×4×6 2 \times 4 \times 6
  • The denominator inside the power: 7×8×9 7 \times 8 \times 9

Therefore, raising each part to the power 3x3x gives us:

(2×4×6)3x(7×8×9)3x \frac{(2\times4\times6)^{3x}}{(7\times8\times9)^{3x}}

Thus, the simplified expression for the given equation is:

(2×4×6)3x(7×8×9)3x \frac{\left(2\times4\times6\right)^{3x}}{\left(7\times8\times9\right)^{3x}}

The solution to the question is: (2×4×6)3x(7×8×9)3x \frac{\left(2\times4\times6\right)^{3x}}{\left(7\times8\times9\right)^{3x}}

3

Final Answer

(2×4×6)3x(7×8×9)3x \frac{\left(2\times4\times6\right)^{3x}}{\left(7\times8\times9\right)^{3x}}

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\( 112^0=\text{?} \)

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