Solve for X: -3(x+1)+5x-4=-3+5(x-1) | Step-by-Step Guide

Linear Equations with Fractional Solutions

Solve for x:

3(x+1)+5x4=3+5(x1) -3(x+1)+5x-4=-3+5(x-1)

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find X
00:04 Open parentheses properly, multiply by each factor
00:29 Collect like terms
00:54 Arrange the equation so that X is isolated on one side
01:10 Collect like terms
01:16 Isolate X
01:24 And this is the solution to the problem

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Solve for x:

3(x+1)+5x4=3+5(x1) -3(x+1)+5x-4=-3+5(x-1)

2

Step-by-step solution

First, we will expand the parentheses on both sides:

3x3+5x4=3+5x5 -3x-3+5x-4=-3+5x-5

Enter the like terms in both sections. Let's start with the left section:

3x+5x=2x -3x+5x=2x

34=7 -3-4=-7

Calculate the like terms on the right side:

35=8 -3-5=-8

Now, we obtain the equation:

2x7=8+5x 2x-7=-8+5x

To the right side we will move the members without the X, while to the left side we move those with the X, keeping the plus and minus signs as appropriate:

2x5x=8+7 2x-5x=-8+7

3x=1 -3x=-1

Finally, we divide both sides by -3:

13=3x3 \frac{-1}{-3}=\frac{-3x}{-3}

13=x \frac{1}{3}=x

3

Final Answer

13 \frac{1}{3}

Key Points to Remember

Essential concepts to master this topic
  • Distributive Property: Expand parentheses first before combining like terms
  • Technique: Move x terms left, constants right: 2x - 5x = -8 + 7
  • Check: Substitute 13 \frac{1}{3} back into original equation ✓

Common Mistakes

Avoid these frequent errors
  • Forgetting to distribute negative signs correctly
    Don't just distribute the coefficient and ignore the negative sign = wrong signs throughout! This creates errors in every step. Always distribute both the coefficient AND the sign to every term inside parentheses.

Practice Quiz

Test your knowledge with interactive questions

\( x+x=8 \)

FAQ

Everything you need to know about this question

Why do I get a fraction instead of a whole number?

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Not all equations have whole number solutions! Fractions are perfectly valid answers. The equation 3(x+1)+5x4=3+5(x1) -3(x+1)+5x-4=-3+5(x-1) naturally leads to x=13 x = \frac{1}{3} .

How do I handle the negative sign in -3(x+1)?

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The negative distributes to every term inside: 3(x+1)=3x3 -3(x+1) = -3x - 3 . Don't forget that negative times positive equals negative!

What's the easiest way to combine like terms?

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Group similar terms together:

  • x terms: 3x+5x=2x -3x + 5x = 2x
  • Constants: 34=7 -3 - 4 = -7
This keeps your work organized!

How can I check if x = 1/3 is correct?

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Substitute back into the original equation. Left side: 3(13+1)+5(13)4=4+534=193 -3(\frac{1}{3}+1)+5(\frac{1}{3})-4 = -4 + \frac{5}{3} - 4 = -\frac{19}{3} . Right side should equal the same value!

Why do I move x terms to one side?

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Isolation strategy! Moving all x terms to one side (like 2x5x=3x 2x - 5x = -3x ) lets you factor out x and solve directly. It's much cleaner than having x on both sides.

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